A shopkeeper cheats to the extent of 9% while buying and selling fruits, by using tampered weights. His total gain in percentage is: A. 18.25 B. 18.81 C. 19.78 D. 18.5
C
This problem involves a shopkeeper who uses tampered weights to cheat during both the buying and selling processes. We need to calculate the total percentage gain the shopkeeper makes due to this dishonesty.
When a shopkeeper cheats using tampered weights, it means they manipulate the quantity of goods involved relative to the price paid or charged. Let's analyze the cheating in buying and selling separately, assuming the cheating is by 9%.
Let's assume the true price of 1 unit of fruit is Rs. 1. We will track the cost and selling price for a specific quantity of fruit.
Consider the purchase where the shopkeeper pays for 100 units.
Cost Price (CP): While buying, the shopkeeper pays the price of 100 units. If the true price of 1 unit is Re 1, the cost incurred is Rs. 100.
Quantity Received: Due to cheating by 9% while buying, the shopkeeper receives 100 + 9 = 109 units of fruit for this cost.
Now, the shopkeeper sells the 109 units of fruit they received.
Selling Price (SP): While selling, the shopkeeper charges the price of 100 units for every 91 units delivered. This means the selling price per unit is \(\frac{\text{Price of 100 units}}{\text{Quantity delivered (91 units)}} = \frac{\text{Rs. 100}}{91 \text{ units}}\). The selling price per unit is Rs. \(\frac{100}{91}\).
The shopkeeper sells 109 units. The total selling price for 109 units will be the quantity multiplied by the selling price per unit: \(\text{SP} = 109 \times \text{Rs. } \frac{100}{91} = \text{Rs. } \frac{10900}{91}\).
Now we can calculate the total gain:
Total Gain = Selling Price - Cost Price
Total Gain = Rs. \(\frac{10900}{91}\) - Rs. 100
Total Gain = Rs. \(\frac{10900 - 100 \times 91}{91}\)
Total Gain = Rs. \(\frac{10900 - 9100}{91}\)
Total Gain = Rs. \(\frac{1800}{91}\)
The gain percentage is calculated on the cost price:
Gain Percentage = \(\left( \frac{\text{Total Gain}}{\text{Cost Price}} \right) \times 100\)
Gain Percentage = \(\left( \frac{1800/91}{100} \right) \times 100\)
Gain Percentage = \(\left( \frac{1800}{91 \times 100} \right) \times 100\)
Gain Percentage = \(\left( \frac{1800}{9100} \right) \times 100\)
Gain Percentage = \(\frac{18}{91} \times 100\)
Calculating the value:
\(\frac{18}{91} \times 100 \approx 0.197802 \times 100 \approx 19.78\)
The total gain in percentage is approximately 19.78%.
Let's compare our calculated gain percentage with the given options:
| Option | Gain Percentage |
|---|---|
| A | 18.25% |
| B | 18.81% |
| C | 19.78% |
| D | 18.5% |
Our calculated value of approximately 19.78% matches option C.
By cheating 9% during both buying (getting more quantity) and selling (giving less quantity), the shopkeeper makes a total gain of 19.78%.
| Concept | Explanation |
|---|---|
| Cheating while Buying (Tampered Weight) | Getting \((100+x)\)% quantity for the price of 100%. Effectively reduces the cost price per unit. |
| Cheating while Selling (Tampered Weight) | Giving \((100-y)\)% quantity for the price of 100%. Effectively increases the selling price per unit. |
| Total Gain Percentage | Calculated as \(\left( \frac{\text{Total Selling Price} - \text{Total Cost Price}}{\text{Total Cost Price}} \right) \times 100\). The CP and SP must be for the same quantity of goods. |
Problems involving faulty weights are common in competitive exams. The key is to correctly interpret how the cheating affects the cost and selling price relative to the actual quantity of goods.
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A shopkeeper cheats to the extent of 11% while buying and selling fruits, by using tampered weights. His total gain in percentage is.
A. 23.25
B. 23.21
C. 24.71
C. 23.5