A synchronous generator rated 11 kV, 50 MVA has a per unit impedance of 0.2 pu on its own base. Then its impedance referred to a 22 kV, 150 MVA base would be
This problem involves converting the per unit (pu) impedance of a synchronous generator from its original base values (rating) to a new set of base values (different MVA and voltage rating). This is a common task in power system analysis.
Per unit impedance represents the impedance relative to a specified base impedance. When the base MVA or base voltage changes, the per unit impedance value also changes accordingly. The actual impedance value (in Ohms) remains constant, but its representation in per unit changes.
The formula used to convert per unit impedance from an old base to a new base is:
$Z_{\text{pu, new}} = Z_{\text{pu, old}} \times \left( \frac{V_{\text{base, old}}}{V_{\text{base, new}}} \right)^2 \times \left( \frac{S_{\text{base, new}}}{S_{\text{base, old}}} \right)$
Where:
From the question, we have the following values:
Now, we substitute these values into the base change formula:
Therefore, the impedance of the synchronous generator referred to the new base of 22 kV, 150 MVA is 0.15 pu.
The relation between the old and new per unit impedance values is given by:
A synchronous generator is rated at 40 MVA, 14.6 kV and 50 Hz. The base impedance of the generator will be
The per unit impedance of a line is X p.u. If base voltage is tripled and base MVA is doubled, the new per unit impedance is: