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Question

A sum of money becomes \( \frac{8}{7} \) of itself in 2 years at a certain rate of simple interest. The rate per annum is:

This question was previously asked in
SSC CGL 2023 (Tier-II) Paper 1 Previous Year Paper (26-Oct-2023) (Shift-1)
The correct answer is \( 7 \frac{1}{7} \% \)

Understanding Simple Interest Calculation

This problem asks us to find the annual rate of simple interest at which a sum of money grows to \( \frac{8}{7} \) times its original value in 2 years. Simple interest is calculated only on the principal amount.

Simple Interest Formulas

The key formulas for simple interest are:

  • Simple Interest (SI) = \( \frac{\text{Principal} \times \text{Rate} \times \text{Time}}{100} \)
  • Amount (A) = Principal (P) + Simple Interest (SI)

From the second formula, we can also write SI = Amount (A) - Principal (P).

Setting up the Problem

Let the original sum of money be the Principal, denoted by \(P\). The problem states that the sum of money becomes \( \frac{8}{7} \) of itself in 2 years. This means the Amount (A) after 2 years is \( \frac{8}{7} \) times the Principal.

  • Principal = \(P\)
  • Amount (A) = \( \frac{8}{7} P \)
  • Time (T) = 2 years
  • We need to find the Rate (R) per annum.

Calculating the Simple Interest Earned

Using the formula SI = A - P, we can find the simple interest earned over the 2 years:

SI = \( \frac{8}{7} P - P \)

To subtract \(P\) from \( \frac{8}{7} P \), we can write \(P\) as \( \frac{7}{7} P \):

SI = \( \frac{8}{7} P - \frac{7}{7} P \)

SI = \( \left(\frac{8}{7} - \frac{7}{7}\right) P \)

SI = \( \frac{8-7}{7} P \)

SI = \( \frac{1}{7} P \)

So, the simple interest earned in 2 years is \( \frac{1}{7} \) of the original Principal.

Finding the Rate Per Annum

Now we use the main simple interest formula: \( \text{SI} = \frac{P \times R \times T}{100} \). We know SI = \( \frac{1}{7} P \), P is the principal, and T = 2 years. We need to solve for R.

\( \frac{1}{7} P = \frac{P \times R \times 2}{100} \)

We can cancel \(P\) from both sides of the equation (assuming \(P \neq 0\)):

\( \frac{1}{7} = \frac{R \times 2}{100} \)

\( \frac{1}{7} = \frac{2R}{100} \)

Simplify the fraction on the right side:

\( \frac{1}{7} = \frac{R}{50} \)

Now, solve for R by cross-multiplying or multiplying both sides by 50:

\( R = 50 \times \frac{1}{7} \)

\( R = \frac{50}{7} \)

Converting to a Mixed Number

The rate is \( \frac{50}{7} \% \). To express this as a mixed number, we divide 50 by 7.

\( 50 \div 7 \)

  • 7 goes into 50, 7 times (since \( 7 \times 7 = 49 \)).
  • The remainder is \( 50 - 49 = 1 \).

So, \( \frac{50}{7} \) can be written as \( 7 \frac{1}{7} \).

The rate per annum is \( 7 \frac{1}{7} \% \).

Summary of Steps

  1. Identify Principal, Amount, and Time from the problem.
  2. Calculate Simple Interest (SI) using the formula SI = Amount - Principal.
  3. Use the Simple Interest formula SI = \( \frac{P \times R \times T}{100} \) to set up an equation.
  4. Solve the equation for the rate (R).
  5. Convert the result to a mixed fraction if necessary.
Problem Data and Calculation Summary
Item Value
Principal (P) \(P\)
Amount (A) \( \frac{8}{7} P \)
Time (T) 2 years
Simple Interest (SI) \( A - P = \frac{8}{7} P - P = \frac{1}{7} P \)
Formula Used \( \text{SI} = \frac{P \times R \times T}{100} \)
Equation \( \frac{1}{7} P = \frac{P \times R \times 2}{100} \)
Calculated Rate (R) \( \frac{50}{7} \% = 7 \frac{1}{7} \% \)

The calculated rate matches option 3.

Revision Table: Simple Interest Concepts

Key Simple Interest Terms and Formulas
Term Definition Formula/Relation
Principal (P) The initial sum of money borrowed or invested. Base amount for interest calculation.
Simple Interest (SI) Interest calculated only on the principal amount. \( \text{SI} = \frac{P \times R \times T}{100} \)
Rate (R) The percentage at which interest is charged or earned per annum. Expressed as a percentage (e.g., 5%). Use R/100 in formula.
Time (T) The duration for which the money is borrowed or invested, usually in years. Must be in years for the standard formula.
Amount (A) The total sum of Principal and Simple Interest after a certain time. \( A = P + \text{SI} \)

Additional Information: Simple vs Compound Interest

It's important to distinguish between simple interest and compound interest, although this problem specifically deals with simple interest.

  • Simple Interest: Interest is calculated solely on the initial principal amount. The interest earned in previous periods is not added to the principal for calculating the next period's interest. This results in a fixed amount of interest earned each period.
  • Compound Interest: Interest is calculated on the principal amount plus any accumulated interest from previous periods. This means the interest earned in each period is added to the principal, and the next period's interest is calculated on this new, larger principal. This leads to exponential growth of the investment or loan.

The formula used in this problem is specifically for simple interest. For compound interest, a different formula is used: \( A = P \left(1 + \frac{R}{100}\right)^T \).

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Similar Questions

  1. If the simple interest at the same interest rate on ₹500 for 4 years and ₹700 for 2 years, combined together, is ₹280, then what is the rate of interest?

  2. A man invests a total sum of Rs. 10,000 in a company. A part of the sum was invested at 10% simple interest per annum and the remaining part at 15% simple interest per annum. If the total interest accrued to him in two years equals Rs. 2,400, the sum invested at 15% simple interest per annum is:

  3. If Rs. 72 amounts to Rs. 104.4 in 3 years, what will Rs. 120 amount to in 5 years at the same rate percent per annum?

  4. A person deposited Rs. 500 for 3 years, Rs. 650 for 5 years, and Rs. 1,250 for 7 years. He received a total simple interest of Rs. 1,620. The rate of interest per annum is: 

  5. A sum of money invested at a certain rate of simple interest per annum amounts to Rs. 14,522 in seven years and to Rs. 18,906 in eleven years. Find the sum invested (in Rs.).

  6. A person took a loan at 5% per annum simple interest during the first year and with an increase of 0.5% simple interest every year from the second year onwards. After 4 years, he paid Rs. 4,600 as a total interest to settle the loan completely. How much was the loan?  

  7. In how many years will a sum of Rs. 9,500 amount to Rs. 11,780 at the rate of 8% per annum at simple interest?

  8. A sum of money at a fixed rate of simple interest amounts to Rs. 1,630 in 3 years and to Rs. 1,708 in 4 years. Find the sum (in Rs.).

  9. A sum of money earns a simple interest at 7.25% per annum for the first eight years, at 8.5% for the next six years, and at 6.5% for the final four years. If the total interest earned during these eighteen years was Rs. 35,100, what was the original sum invested (in Rs.)?

  10. A certain amount is lent at x% p.a. simple interest for 3 years. Instead, if the amount was lent at 3x% p.a. simple interest for 'y' more years, then the simple interest would have been seven times the earlier interest. What is the value of y?


Important Questions from Simple Interest

  1. If ₹12,800 is invested in a bank for 5 years at the rate of 9% per annum simple interest. what amount is returned by the bank?

  2. Somu has borrowed ₹10,000 from a money lender with simple interest at a rate of 7% half yearly. How much amount will he pay to the money lender after 3 years?

  3. Find the Simple interest on Rs. 2,400 from 20 March 2019 to 31 may 2019 at \(6{1 \over 4}\) % rate?

  4. If the simple interest for five years is equal is 35% of the principal, that rate of interest is:

  5. A sum fetched a simple interest of Rs. 3,040 at the rate of 8% p.a in 5 years. what is the sum?

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