This section details the calculation for finding the annual compound interest rate given the principal, final amount, and time period.
The standard formula for the amount ($A$) accumulated with compound interest is:
$ A = P \left(1 + \frac{R}{100}\right)^n $
Where:
$ 24389 = 15625 \left(1 + \frac{R}{100}\right)^3 $
$ \left(1 + \frac{R}{100}\right)^3 = \frac{24389}{15625} $
$ 1 + \frac{R}{100} = \sqrt[3]{\frac{29^3}{25^3}} $
$ 1 + \frac{R}{100} = \frac{29}{25} $
$ \frac{R}{100} = \frac{29}{25} - 1 $
$ \frac{R}{100} = \frac{29 - 25}{25} = \frac{4}{25} $
$ R = \frac{4}{25} \times 100 $
$ R = 16 $
The annual rate of interest is 16%.
The certain sum amounts to Rs. 9,982.50 in \(2\frac{1}{2}\) years at 12% p.a., interest compounded 10-monthly. The sum (in Rs.) is:
The difference between the simple interest and the compound interest compounded annually on a certain sum of money for 2 years at a rate of 8% per annum is Rs. 16.80. Find the principle amount.
If a sum of ₹ 2000 is lent at 10% p.a. compound interest, what is the interest for the second year?
A sum becomes 5 times of itself in 3 years. at compound interest (interest is compounded annually). In how many years. will the sum becomes 125 times of itself?
If the compound interest on a certain sum of money for two years at 9% p.a. is Rs. 3,762, then the sum is: