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Question

A sum of ₹15,625 amounts to ₹24,389 in 3 years at a certain rate of interest per annum, compounded annually. The rate of interest per annum is:

This question was previously asked in
RRB NTPC 2024 CBT 1 Question Paper (28-Aug-2025) (Shift 3)
The correct answer is
$16\%$

Compound Interest Rate Calculation

This section details the calculation for finding the annual compound interest rate given the principal, final amount, and time period.

Problem Statement Details

  • Principal Amount ($P$) = ₹15,625
  • Final Amount ($A$) after 3 years = ₹24,389
  • Time period ($n$) = 3 years
  • Interest compounded annually.

Compound Interest Formula

The standard formula for the amount ($A$) accumulated with compound interest is:

$ A = P \left(1 + \frac{R}{100}\right)^n $

Where:

  • $A$ is the final amount
  • $P$ is the principal amount
  • $R$ is the annual interest rate (in percent)
  • $n$ is the number of years

Step-by-Step Calculation

  1. Substitute the known values ($P=15625$, $A=24389$, $n=3$) into the formula:

    $ 24389 = 15625 \left(1 + \frac{R}{100}\right)^3 $

  2. Isolate the term $\left(1 + \frac{R}{100}\right)^3$:

    $ \left(1 + \frac{R}{100}\right)^3 = \frac{24389}{15625} $

  3. Calculate the cube root of both sides. Note that $15625 = 25^3$ and $24389 = 29^3$:

    $ 1 + \frac{R}{100} = \sqrt[3]{\frac{29^3}{25^3}} $

    $ 1 + \frac{R}{100} = \frac{29}{25} $

  4. Solve for $\frac{R}{100}$:

    $ \frac{R}{100} = \frac{29}{25} - 1 $

    $ \frac{R}{100} = \frac{29 - 25}{25} = \frac{4}{25} $

  5. Determine the rate $R$:

    $ R = \frac{4}{25} \times 100 $

    $ R = 16 $

Result

The annual rate of interest is 16%.

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Similar Questions

  1. A sum of money doubles itself at a compound interest in 15 years. In how many years will it become 8 times the original amount?
  2. A man placed a fixed deposit of ₹16,000 for a period of 2 years at 10% compound interest. If the interest is compounded half-yearly, then how much amount (in ₹) will he receive after the full term?
  3. A sum is invested at compound interest payable annually. The interest in two successive years was ₹225 and ₹236.25. Find the rate of interest.
  4. A sum of ₹20,000 is borrowed by Heena for 2 years at an interest of 8% compounded annually. Find the compound interest.
  5. The compound interest on ₹20,000 at 8% per annum is ₹3,328. The period in years is:
  6. A sum was invested for 3 years on compound interest at 6%, 12% and 18% in first, second and third year respectively. The sum amounts to ₹20,000 in 3 years. Find the principal amount.
  7. In what time will ₹ $1,000$ become ₹ $1,331$ at an interest rate of $10\%$ per annum compounded annually?
  8. Find the compound interest when the principle is ₹6,000 at an interest of 10% per annum for 2 years.
  9. The population of a town increases at the rate of 10% every year. The present population is 1,000. In how many years will the population become 1,331?
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Important Questions from Compound Interest

  1. The certain sum amounts to Rs. 9,982.50 in \(2\frac{1}{2}\)  years at 12% p.a., interest compounded 10-monthly. The sum (in Rs.) is:

  2. The difference between the simple interest and the compound interest compounded annually on a certain sum of money for 2 years at a rate of 8% per annum is Rs. 16.80. Find the principle amount. 

  3. If a sum of ₹ 2000 is lent at 10% p.a. compound interest, what is the interest for the second year?

  4. A sum becomes 5 times of itself in 3 years. at compound interest (interest is compounded annually). In how many years. will the sum becomes 125 times of itself?

  5. If the compound interest on a certain sum of money for two years at 9% p.a. is Rs. 3,762, then the sum is:

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