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Question

A sum invested at 10% p.a. for 2 years becomes ₹ 3,267, when the interest is compounded annually. What will be the simple interest on the same sum at the same rate in $2\frac{1}{2}$ years ?

The correct answer is
₹ 675

Understanding the Compound Interest Problem

The question requires us to first determine the original amount of money (the principal) that was invested. We are told that this investment grew to ₹ 3,267 over a period of 2 years, earning an interest rate of 10% per year, compounded annually.

Calculating the Principal Sum

To find the principal sum ($P$), we can use the formula for the final amount ($A$) when interest is compounded annually:

$$ A = P \left(1 + \frac{R}{100}\right)^T $$

In this formula:

  • $A$ represents the final amount, which is ₹ 3,267.
  • $P$ represents the principal sum, which we need to find.
  • $R$ represents the annual interest rate, given as 10%.
  • $T$ represents the time period in years, given as 2 years.

Let's substitute the known values into the formula:

$$ 3267 = P \left(1 + \frac{10}{100}\right)^2 $$

First, simplify the term inside the parentheses:

$$ 1 + \frac{10}{100} = 1 + 0.1 = 1.1 $$

Now substitute this back into the equation:

$$ 3267 = P (1.1)^2 $$

Calculate the value of $(1.1)^2$:

$$ (1.1)^2 = 1.21 $$

The equation becomes:

$$ 3267 = P \times 1.21 $$

To find the principal ($P$), we rearrange the equation:

$$ P = \frac{3267}{1.21} $$

Performing the division gives us:

$$ P = 2700 $$

Therefore, the original sum invested was ₹ 2,700.

Calculating the Simple Interest

The question now asks for the simple interest earned on this same principal sum (₹ 2,700) at the same interest rate (10% per year) but over a different time period: $2\frac{1}{2}$ years.

The formula for calculating simple interest ($SI$) is:

$$ SI = \frac{P \times R \times T}{100} $$

Where:

  • $SI$ is the simple interest we want to calculate.
  • $P$ is the principal sum, which is ₹ 2,700.
  • $R$ is the annual interest rate, which is 10%.
  • $T$ is the time period in years.

First, let's express the time period $T$ as a decimal:

$$ T = 2\frac{1}{2} \text{ years} = 2.5 \text{ years} $$

Now, substitute the values of $P$, $R$, and $T$ into the simple interest formula:

$$ SI = \frac{2700 \times 10 \times 2.5}{100} $$

Calculate the product in the numerator:

$$ SI = \frac{27000 \times 2.5}{100} $$

$$ SI = \frac{67500}{100} $$

Finally, perform the division to find the simple interest:

$$ SI = 675 $$

Final Answer Summary

The simple interest calculated on the principal sum of ₹ 2,700 at an annual rate of 10% for $2\frac{1}{2}$ years is ₹ 675.

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Important Questions from Simple and Compound Both

  1. What is the compound interest (in Rs.) at the rate of 10%, compounded annually, for 3 years on the principal which in 8 years at the rate of 12% per annum gives Rs. 4,800 as simple interest?

  2. A certain sum amounts to Rs. 15,500 in 2 years at 12% p.a. simple interest. If the same sum is compounded half-yearly at 10% per annum for \(1 \frac{1}{2}\) years, what will be the amount received? 

  3. The difference in compound interest on a certain sum at 10% p.a. for one year, when the interest is compounded half-yearly and yearly, is Rs. 88.80. What is the simple interest on the same sum for \(1\frac{2}{3}\) years at the same rate?

  4. A sum of Rs. 7500 amounts to Rs. 9075 at 10% p.a, interest being compounded yearly in a certain time. The simple interest (in Rs.) on the same sum for the same time and the same rate is:

  5. A certain sum amounts to Rs.291600 in 2 years and to Rs.314928 in 3 years on compound interest compounded annually. How much will be the simple interest (in Rs.) on Rs.40000 at the same rate for 2 years?

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