The question requires us to first determine the original amount of money (the principal) that was invested. We are told that this investment grew to ₹ 3,267 over a period of 2 years, earning an interest rate of 10% per year, compounded annually.
To find the principal sum ($P$), we can use the formula for the final amount ($A$) when interest is compounded annually:
$$ A = P \left(1 + \frac{R}{100}\right)^T $$
In this formula:
Let's substitute the known values into the formula:
$$ 3267 = P \left(1 + \frac{10}{100}\right)^2 $$
First, simplify the term inside the parentheses:
$$ 1 + \frac{10}{100} = 1 + 0.1 = 1.1 $$
Now substitute this back into the equation:
$$ 3267 = P (1.1)^2 $$
Calculate the value of $(1.1)^2$:
$$ (1.1)^2 = 1.21 $$
The equation becomes:
$$ 3267 = P \times 1.21 $$
To find the principal ($P$), we rearrange the equation:
$$ P = \frac{3267}{1.21} $$
Performing the division gives us:
$$ P = 2700 $$
Therefore, the original sum invested was ₹ 2,700.
The question now asks for the simple interest earned on this same principal sum (₹ 2,700) at the same interest rate (10% per year) but over a different time period: $2\frac{1}{2}$ years.
The formula for calculating simple interest ($SI$) is:
$$ SI = \frac{P \times R \times T}{100} $$
Where:
First, let's express the time period $T$ as a decimal:
$$ T = 2\frac{1}{2} \text{ years} = 2.5 \text{ years} $$
Now, substitute the values of $P$, $R$, and $T$ into the simple interest formula:
$$ SI = \frac{2700 \times 10 \times 2.5}{100} $$
Calculate the product in the numerator:
$$ SI = \frac{27000 \times 2.5}{100} $$
$$ SI = \frac{67500}{100} $$
Finally, perform the division to find the simple interest:
$$ SI = 675 $$
The simple interest calculated on the principal sum of ₹ 2,700 at an annual rate of 10% for $2\frac{1}{2}$ years is ₹ 675.
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The difference in compound interest on a certain sum at 10% p.a. for one year, when the interest is compounded half-yearly and yearly, is Rs. 88.80. What is the simple interest on the same sum for \(1\frac{2}{3}\) years at the same rate?
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