The problem asks for the original marked price, denoted as \(x\). We are given the final selling price after a discount and VAT application. We need to reverse these steps to find \(x\). The steps involve calculating the price before VAT and then the price before the discount.
The selling price is ₹378, which includes a 44% VAT charged on the discounted price. Let the discounted price be \(D\). The formula is:
Selling Price = \(D \times (1 + \text{VAT Rate})\)
Substituting the given values:
\(378 = D \times (1 + 0.44)\)
\(378 = D \times 1.44\)
Now, solve for \(D\):
\(D = \frac{378}{1.44}\)
\(D = 262.5\)
So, the discounted price was ₹262.5.
The shopkeeper offered a 65% discount on the marked price (\(x\)) to get the discounted price \(D\). The relationship is:
Discounted Price = Marked Price \(\times (1 - \text{Discount Rate})\)
Substituting the values:
\(262.5 = x \times (1 - 0.65)\)
\(262.5 = x \times 0.35\)
Now, solve for \(x\):
\(x = \frac{262.5}{0.35}\)
\(x = 750\)
Therefore, the original marked price \(x\) is ₹750.
In a clearance sale of electronic items, an item whose marked price was ₹12,225 is now sold for ₹10,756. d% is the discount percentage on the item. The value of d is:
The list price of an article is ₹5,000 and a discount of 70% is offered on the list price. What additional discount per cent on the already discounted price must be offered to a customer to bring the net selling price to ₹1,275?
The cost price of a toy is ₹210. What should be its marked price so that, after a discount of 5%, the shopkeeper gains 90%?
A scheme like 'Buy 5, Get 6' on the same kind of articles with the same marked price offers a _______ discount.
Two successive discounts of 10% and 5% are equivalent to a single discount of______.
Two successive discounts of 40% and 60% on a deal equivalent to a single discount of: