The problem asks for the original marked price, denoted as \(x\). We are given the final selling price after a discount and VAT application. We need to reverse these steps to find \(x\). The steps involve calculating the price before VAT and then the price before the discount.
The selling price is ₹378, which includes a 44% VAT charged on the discounted price. Let the discounted price be \(D\). The formula is:
Selling Price = \(D \times (1 + \text{VAT Rate})\)
Substituting the given values:
\(378 = D \times (1 + 0.44)\)
\(378 = D \times 1.44\)
Now, solve for \(D\):
\(D = \frac{378}{1.44}\)
\(D = 262.5\)
So, the discounted price was ₹262.5.
The shopkeeper offered a 65% discount on the marked price (\(x\)) to get the discounted price \(D\). The relationship is:
Discounted Price = Marked Price \(\times (1 - \text{Discount Rate})\)
Substituting the values:
\(262.5 = x \times (1 - 0.65)\)
\(262.5 = x \times 0.35\)
Now, solve for \(x\):
\(x = \frac{262.5}{0.35}\)
\(x = 750\)
Therefore, the original marked price \(x\) is ₹750.
A single discount equivalent to two successive discounts of 15% and 25% is:
Ramesh purchases 75 articles for ₹ 10800 and sells them at a loss equal to the selling price of 5 articles. What will be the selling price of one article?
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A shopkeeper marks the marked price of an article 30% more than its real price and offers 10% discount. What is the gain percentage?
An article was sold for Rs. 1,215 after giving a discount of 19%. If a discount of 17.5% is given, then for how much (in Rs.) should the article be sold?