A parallelogram is formed when two distinct lines from one set of parallel lines intersect with two distinct lines from another set of parallel lines.
We have two sets of parallel lines:
To form a parallelogram, we need to choose 2 lines from Set 1 and 2 lines from Set 2.
The number of ways to choose 2 lines from a set of 'n' lines is given by the combination formula $\binom{n}{2}$, which is calculated as:
$ \binom{n}{2} = \frac{n!}{2!(n-2)!} = \frac{n \times (n-1)}{2} $
Number of ways to choose 2 lines from the 4 parallel lines in Set 1:
$ \binom{4}{2} = \frac{4 \times (4-1)}{2} = \frac{4 \times 3}{2} = \frac{12}{2} = 6 $
Number of ways to choose 2 lines from the 5 parallel lines in Set 2:
$ \binom{5}{2} = \frac{5 \times (5-1)}{2} = \frac{5 \times 4}{2} = \frac{20}{2} = 10 $
To find the total number of parallelograms, multiply the number of ways to choose lines from each set:
Total Parallelograms = (Ways to choose from Set 1) $\times$ (Ways to choose from Set 2)
Total Parallelograms = $ \binom{4}{2} \times \binom{5}{2} = 6 \times 10 = 60 $
Therefore, 60 parallelograms are formed by the intersection of these two sets of parallel lines.
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