A ray is incident normally on the face of a triangular prism of refracting angle of 60°. The refractive index of the prism is 2/√3. The angle of deviation will be:
30°
This problem involves analyzing the path of a light ray through a triangular prism and calculating the total angle of deviation. We are given the refracting angle of the prism, the refractive index of the prism material, and the condition that the ray is incident normally on one face.
When a ray of light is incident normally on a surface (angle of incidence \( i_1 = 0^\circ \)), it passes straight through without bending. According to Snell's Law:
\( \mu_1 \sin i_1 = \mu_2 \sin r_1 \)
Here, \(\mu_1\) is the refractive index of the medium outside the prism (usually air, \(\mu_1 \approx 1\)), and \(\mu_2\) is the refractive index of the prism (\(\mu_2 = \mu = \frac{2}{\sqrt{3}}\)). \(i_1\) is the angle of incidence, and \(r_1\) is the angle of refraction inside the prism.
\( 1 \times \sin 0^\circ = \mu \sin r_1 \)
\( 0 = \mu \sin r_1 \)
Since \(\mu \neq 0\), we must have \(\sin r_1 = 0\), which means \( r_1 = 0^\circ \). So, the ray enters the prism without any deviation at the first face.
Inside the prism, the ray travels towards the second refracting face. The angles \(r_1\) and \(r_2\) (angle of refraction at the first face and angle of incidence on the second face, respectively) and the refracting angle \(A\) of the prism are related by the prism formula:
\( A = r_1 + r_2 \)
Substituting the values we know:
\( 60^\circ = 0^\circ + r_2 \)
\( r_2 = 60^\circ \)
Thus, the angle of incidence on the second face of the prism is \( 60^\circ \).
To determine if the ray emerges from the second face or undergoes Total Internal Reflection (TIR), we need to compare the angle of incidence on the second face (\(r_2\)) with the critical angle (\(C\)) for the prism material.
The critical angle \(C\) is given by:
\( \sin C = \frac{1}{\mu} \)
Substituting the refractive index \(\mu = \frac{2}{\sqrt{3}}\):
\( \sin C = \frac{1}{2/\sqrt{3}} = \frac{\sqrt{3}}{2} \)
This value of sine corresponds to an angle of \( 60^\circ \). So, the critical angle \( C = 60^\circ \).
We found that the angle of incidence on the second face is \( r_2 = 60^\circ \). Since \( r_2 = C \), the ray will graze along the second surface or emerge at an angle of \( 90^\circ \) to the normal (i.e., parallel to the surface).
When the angle of incidence on the second face is equal to the critical angle (\(r_2 = C\)), the angle of emergence (\(i_2\)) is \( 90^\circ \). We can verify this using Snell's Law at the second face:
\( \mu \sin r_2 = 1 \sin i_2 \)
\( \frac{2}{\sqrt{3}} \times \sin 60^\circ = \sin i_2 \)
\( \frac{2}{\sqrt{3}} \times \frac{\sqrt{3}}{2} = \sin i_2 \)
\( 1 = \sin i_2 \)
This gives \( i_2 = 90^\circ \). The ray emerges parallel to the second face.
The total angle of deviation (\(\delta\)) produced by the prism is given by the formula:
\( \delta = (i_1 + i_2) - A \)
Substituting the values \( i_1 = 0^\circ \), \( i_2 = 90^\circ \), and \( A = 60^\circ \):
\( \delta = (0^\circ + 90^\circ) - 60^\circ \)
\( \delta = 90^\circ - 60^\circ \)
\( \delta = 30^\circ \)
The angle of deviation is \( 30^\circ \).
| Parameter | Value |
|---|---|
| Refracting Angle (A) | 60° |
| Refractive Index (μ) | \( \frac{2}{\sqrt{3}} \) |
| Incidence Angle (First Face) (i₁) | 0° (Normal Incidence) |
| Refraction Angle (First Face) (r₁) | 0° |
| Incidence Angle (Second Face) (r₂) | 60° |
| Critical Angle (C) | 60° |
| Emergence Angle (Second Face) (i₂) | 90° |
| Angle of Deviation (δ) | 30° |
| Concept | Description | Formula/Condition |
|---|---|---|
| Snell's Law | Relates the angle of incidence and refraction at an interface between two media. | \( \mu_1 \sin \theta_1 = \mu_2 \sin \theta_2 \) |
| Prism Formula | Relates the refracting angle of the prism to the angles inside the prism at both faces. | \( A = r_1 + r_2 \) |
| Angle of Deviation | The angle between the direction of the incident ray and the emergent ray. | \( \delta = (i_1 + i_2) - A \) |
| Critical Angle (C) | The angle of incidence in the denser medium for which the angle of refraction in the rarer medium is 90°. | \( \sin C = \frac{\mu_{rarer}}{\mu_{denser}} \) |
| Total Internal Reflection (TIR) | Occurs when light traveling from a denser to a rarer medium is incident at an angle greater than the critical angle. | \( r_2 > C \) (for emergence from second face) |
A triangular prism is a transparent optical element with flat, polished surfaces that refract light. The shape of the prism allows it to deviate light rays or disperse light into its constituent colors (spectrum).
In this specific problem, the angle of incidence on the second face was exactly equal to the critical angle, resulting in the ray emerging parallel to that face (\(i_2 = 90^\circ\)) and producing a deviation of \( 30^\circ \).
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