A pump can fill a tank in 3 hours. Due to a leak in the tank, it takes 4.5 hours to fill the tank. In how much time can the leak empty the full tank if no other entry or exit routes are open?
9 hours
The pump alone fills 1/3 of the tank per hour.
With the leak acting, the effective filling rate is 1/4.5 = 2/9 of the tank per hour.
Leak's emptying rate = pump rate − effective rate = \(\frac{1}{3}-\frac{2}{9}=\frac{3-2}{9}=\frac{1}{9}\) per hour.
Emptying 1/9 of the tank each hour, the leak drains the full tank in 9 hours.
Hence, the answer is 9 hours.
Similar Questions
Three pipes A, B and C can fill a tank in 12 hours, 18 hours and 24 hours, respectively. A leak at the bottom can empty the full tank in 36 hours. If all the pipes are opened together, in how many hours will the tank be filled? (Round off your answer to two decimal places.)
Pipes A and B can fill an entire tank in 8 hours and 12 hours, respectively. The water
tank is one-fourth full. If both the pipes are opened together, then how long will it take
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Important Questions from Pipe and Cistern
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Two pipes A and B can fill a tank in 12 minutes and 24 minutes, respectively, while a third pipe C can empty the full tank in 32 minutes. All the three pipes are opened simultaneously. However, pipe C is closed 2 minutes before the tank is filled. In how much time (in minutes) will the tank be full?
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Pipes A and B can fill a tank in 43.2 minutes and 108 minutes, respectively. Pipe C can empty it at 3 litres/minute. When all the three pipes are opened together, they fill the tank in 54 minutes. The capacity (in litres) of the tank is:
