This question requires calculating the original price before discounts were applied.
Calculating Original Price with Successive Discounts
Let the original price of the product be P.
Two successive discounts are applied: 20% and 10%.
- After the first discount of 20%, the remaining price is (100% - 20%) = 80% of the original price.
- After the second discount of 10% on the new price, the final price is (100% - 10%) = 90% of the price after the first discount.
The final price after both discounts is given as ₹7,200.
Step-by-Step Solution
- Represent the discounts mathematically. The price after the first discount is \(P \times (1 - 0.20) = P \times 0.80\).
- Calculate the price after the second discount. This is applied to the price obtained in the previous step: \((P \times 0.80) \times (1 - 0.10) = P \times 0.80 \times 0.90\).
- Set up the equation with the final price: \(P \times 0.80 \times 0.90 = 7200\).
- Simplify the discount multiplication: \(P \times 0.72 = 7200\).
- Solve for the original price P by dividing the final price by the combined discount factor: \(P = \frac{7200}{0.72}\).
- Calculate the final value: \(P = 10000\).
Therefore, the original price of the product was ₹10,000.
Important Questions from Discount and MP
A single discount equivalent to two successive discounts of 15% and 25% is:
Ramesh purchases 75 articles for ₹ 10800 and sells them at a loss equal to the selling price of 5 articles. What will be the selling price of one article?
A TV was available for Rs. 14,500. The price came down to Rs. 11,890 during the Diwali sale. What is the percentage discount?
A shopkeeper marks the marked price of an article 30% more than its real price and offers 10% discount. What is the gain percentage?
An article was sold for Rs. 1,215 after giving a discount of 19%. If a discount of 17.5% is given, then for how much (in Rs.) should the article be sold?
