This question requires calculating the original price before discounts were applied.
Calculating Original Price with Successive Discounts
Let the original price of the product be P.
Two successive discounts are applied: 20% and 10%.
- After the first discount of 20%, the remaining price is (100% - 20%) = 80% of the original price.
- After the second discount of 10% on the new price, the final price is (100% - 10%) = 90% of the price after the first discount.
The final price after both discounts is given as ₹7,200.
Step-by-Step Solution
- Represent the discounts mathematically. The price after the first discount is \(P \times (1 - 0.20) = P \times 0.80\).
- Calculate the price after the second discount. This is applied to the price obtained in the previous step: \((P \times 0.80) \times (1 - 0.10) = P \times 0.80 \times 0.90\).
- Set up the equation with the final price: \(P \times 0.80 \times 0.90 = 7200\).
- Simplify the discount multiplication: \(P \times 0.72 = 7200\).
- Solve for the original price P by dividing the final price by the combined discount factor: \(P = \frac{7200}{0.72}\).
- Calculate the final value: \(P = 10000\).
Therefore, the original price of the product was ₹10,000.
Similar Questions
- Two successive discounts of 25% and 10% on a deal are equivalent to a single discount of:
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Important Questions from Discount and MP
- Two successive discounts of 25% and 10% on a deal are equivalent to a single discount of:
- A shopkeeper offers the following three schemes. Which scheme has the maximum discount percent?
I. Two successive discounts of 15% and 20%.
II. Buy 4 get 2 free.
III. Buy 6 get 4 free - A shopkeeper is given a 10% trade discount and a 5% scheme discount (free units). On purchasing 100 units priced at ₹50 each, what is the trade discount amount?
- What is the equivalent single discount for successive discounts of 20% and 10%?
- Rahul buys a box of pens (listed price of ₹900) with a trade discount of 30%. What is the net price?
