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Question

A person travelled 80 km in 6 hours. If the person travelled the first part with a uniform speed of 10 kmph and the remaining part with a uniform speed of 18kmph.
What percentage of the total distance is travelled at a uniform speed of 10 kmph?

The correct answer is
43.75

Distance Percentage Calculation at 10 kmph

The problem asks for the percentage of the total distance travelled at a specific speed (10 kmph). We are given the total distance, total time, and two different speeds for two parts of the journey.

Calculating Travelled Distance Percentage

Let's define the variables:

  • Total Distance ($D$) = 80 km
  • Total Time ($T$) = 6 hours
  • Speed for the first part ($v_1$) = 10 kmph
  • Speed for the remaining part ($v_2$) = 18 kmph
  • Let $d_1$ be the distance travelled at $v_1$, and $t_1$ be the time taken.
  • Let $d_2$ be the distance travelled at $v_2$, and $t_2$ be the time taken.

Setting Up Equations

We know that the sum of distances equals the total distance and the sum of times equals the total time:

  1. Distance equation: $d_1 + d_2 = D \implies d_1 + d_2 = 80$ km
  2. Time equation: $t_1 + t_2 = T \implies t_1 + t_2 = 6$ hours

Using the formula distance = speed × time ($d = v \times t$), we can express $d_1$ and $d_2$:

  • $d_1 = v_1 \times t_1 = 10 t_1$
  • $d_2 = v_2 \times t_2 = 18 t_2$

Solving for Time ($t_1$)

Substitute the expressions for $d_1$ and $d_2$ into the distance equation:

$10 t_1 + 18 t_2 = 80$

From the time equation, we can express $t_2$ in terms of $t_1$: $t_2 = 6 - t_1$. Substitute this into the equation above:

$10 t_1 + 18 (6 - t_1) = 80$

Now, solve for $t_1$:

$10 t_1 + 108 - 18 t_1 = 80$

$-8 t_1 = 80 - 108$

$-8 t_1 = -28$

$t_1 = \frac{-28}{-8} = \frac{28}{8} = 3.5 \text{ hours}$

Calculating Distance ($d_1$)

Now that we have $t_1$, we can find the distance travelled at 10 kmph:

$d_1 = 10 \times t_1 = 10 \times 3.5 = 35 \text{ km}$

Calculating Percentage of Total Distance

Finally, calculate the percentage of the total distance travelled at 10 kmph:

$\text{Percentage} = \frac{d_1}{D} \times 100$

$\text{Percentage} = \frac{35 \text{ km}}{80 \text{ km}} \times 100$

$\text{Percentage} = \frac{35}{80} \times 100 = \frac{35}{8} \times 10 = \frac{350}{8} = 43.75\%$

The percentage of the total distance travelled at a uniform speed of 10 kmph is 43.75%.

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Important Questions from Speed Distance and Time

  1. Two cars, P and Q, start from a point X in India at 10 AM. Car P travels North with a speed of 25 km/h and car Q travels East with a speed of 30 km/h. Car P travels continuously but car Q stops for some time after travelling for one hour. If both the cars are at the same distance from X at 11:30 AM, for how long (in minutes) did car Q stop?
  2. In a 500 m race, P and Q have speeds in the ratio of 3: 4. Q starts the race when P has already covered 140 m. 
    What is the distance between P and Q (in m) when P wins the race?

  3. A vehicle is moving at a speed of 12 m/s on a level road. It applies emergency brakes and starts to skid without rolling in a straight path. The deceleration of the vehicle is constant after braking and it comes to rest at a distance of 15 m. Assuming, $g = 10$ m/s$^2$, the coefficient of kinetic friction between the tyres and road is  _________ [round off to 2 decimal places]

  4. The distance between Delhi and Agra is 233 km. A car P started travelling from Delhi to Agra and another car Q started from Agra to Delhi along the same road 1 hour after the car P started. The two cars crossed each other 75 minutes after the car Q started. Both cars were travelling at constant speed. The speed of car P was 10 km/hr more than the speed of car Q. How many kilometers the car Q had travelled when the cars crossed each other?
  5. Two trains started at 7AM from the same point. The first train travelled north at a speed of 80km/h and the second train travelled south at a speed of 100 km/h. The time at which they were 540 km apart is  _______________ AM.

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