What percentage of the total distance is travelled at a uniform speed of 10 kmph?
The problem asks for the percentage of the total distance travelled at a specific speed (10 kmph). We are given the total distance, total time, and two different speeds for two parts of the journey.
Let's define the variables:
We know that the sum of distances equals the total distance and the sum of times equals the total time:
Using the formula distance = speed × time ($d = v \times t$), we can express $d_1$ and $d_2$:
Substitute the expressions for $d_1$ and $d_2$ into the distance equation:
$10 t_1 + 18 t_2 = 80$
From the time equation, we can express $t_2$ in terms of $t_1$: $t_2 = 6 - t_1$. Substitute this into the equation above:
$10 t_1 + 18 (6 - t_1) = 80$
Now, solve for $t_1$:
$10 t_1 + 108 - 18 t_1 = 80$
$-8 t_1 = 80 - 108$
$-8 t_1 = -28$
$t_1 = \frac{-28}{-8} = \frac{28}{8} = 3.5 \text{ hours}$
Now that we have $t_1$, we can find the distance travelled at 10 kmph:
$d_1 = 10 \times t_1 = 10 \times 3.5 = 35 \text{ km}$
Finally, calculate the percentage of the total distance travelled at 10 kmph:
$\text{Percentage} = \frac{d_1}{D} \times 100$
$\text{Percentage} = \frac{35 \text{ km}}{80 \text{ km}} \times 100$
$\text{Percentage} = \frac{35}{80} \times 100 = \frac{35}{8} \times 10 = \frac{350}{8} = 43.75\%$
The percentage of the total distance travelled at a uniform speed of 10 kmph is 43.75%.
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