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Question

A person travelled 80 km in 6 hours. If the person travelled the first part with a uniform speed of 10 kmph and the remaining part with a uniform speed of 18kmph.
What percentage of the total distance is travelled at a uniform speed of 10 kmph?

The correct answer is
43.75

Distance Percentage Calculation at 10 kmph

The problem asks for the percentage of the total distance travelled at a specific speed (10 kmph). We are given the total distance, total time, and two different speeds for two parts of the journey.

Calculating Travelled Distance Percentage

Let's define the variables:

  • Total Distance ($D$) = 80 km
  • Total Time ($T$) = 6 hours
  • Speed for the first part ($v_1$) = 10 kmph
  • Speed for the remaining part ($v_2$) = 18 kmph
  • Let $d_1$ be the distance travelled at $v_1$, and $t_1$ be the time taken.
  • Let $d_2$ be the distance travelled at $v_2$, and $t_2$ be the time taken.

Setting Up Equations

We know that the sum of distances equals the total distance and the sum of times equals the total time:

  1. Distance equation: $d_1 + d_2 = D \implies d_1 + d_2 = 80$ km
  2. Time equation: $t_1 + t_2 = T \implies t_1 + t_2 = 6$ hours

Using the formula distance = speed × time ($d = v \times t$), we can express $d_1$ and $d_2$:

  • $d_1 = v_1 \times t_1 = 10 t_1$
  • $d_2 = v_2 \times t_2 = 18 t_2$

Solving for Time ($t_1$)

Substitute the expressions for $d_1$ and $d_2$ into the distance equation:

$10 t_1 + 18 t_2 = 80$

From the time equation, we can express $t_2$ in terms of $t_1$: $t_2 = 6 - t_1$. Substitute this into the equation above:

$10 t_1 + 18 (6 - t_1) = 80$

Now, solve for $t_1$:

$10 t_1 + 108 - 18 t_1 = 80$

$-8 t_1 = 80 - 108$

$-8 t_1 = -28$

$t_1 = \frac{-28}{-8} = \frac{28}{8} = 3.5 \text{ hours}$

Calculating Distance ($d_1$)

Now that we have $t_1$, we can find the distance travelled at 10 kmph:

$d_1 = 10 \times t_1 = 10 \times 3.5 = 35 \text{ km}$

Calculating Percentage of Total Distance

Finally, calculate the percentage of the total distance travelled at 10 kmph:

$\text{Percentage} = \frac{d_1}{D} \times 100$

$\text{Percentage} = \frac{35 \text{ km}}{80 \text{ km}} \times 100$

$\text{Percentage} = \frac{35}{80} \times 100 = \frac{35}{8} \times 10 = \frac{350}{8} = 43.75\%$

The percentage of the total distance travelled at a uniform speed of 10 kmph is 43.75%.

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Important Questions from Speed Distance and Time

  1. A car is moving on a horizontal surface in a straight line with a constant velocity of 3 m/s. A ball is thrown vertically upwards at time $t = 0$ from the top of the moving car with a velocity of 20 m/s. The acceleration due to gravity is 10 m/s$^2$.
    At what value(s) of time $t$ in second(s), the ball is at a height of 15 m from the top of the moving car?
  2. Velocity of an object fired directly in upward direction is given by $V = 80 – 32 \ t$, where $t$ (time) is in seconds. When will the velocity be between 32 m/sec and 64 m/sec?
  3. In a 500 m race, P and Q have speeds in the ratio of 3: 4. Q starts the race when P has already covered 140 m. 
    What is the distance between P and Q (in m) when P wins the race?

  4. An automobile travels from city A to city B and returns to city A by the same route. The speed of the vehicle during the onward and return journeys were constant at 60 km/h and 90 km/h, respectively. What is the average speed in km/h for the entire journey?
  5. Two cars start at the same time from the same location and go in the same direction. The speed of the first car is 50 km/h and the speed of the second car is 60 km/h. The number of hours it takes for the distance between the two cars to be 20 km is ___________.

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