A person standing on level ground looks up at the top of a vertical tower. The angle of elevation formed at the observer's eye is 60°. If the tower is 18 m high, determine the horizontal distance (in meters) between the person and the base of the tower.
6\(\sqrt3\)
Using \(\tan60^\circ = \dfrac{\text{height}}{\text{distance}}\): \(\sqrt3 = \dfrac{18}{d}\).
\(d = \dfrac{18}{\sqrt3} = \dfrac{18\sqrt3}{3} = 6\sqrt3\).
Hence, the horizontal distance between the person and the base of the tower is \(6\sqrt3\) meters.
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2. x can be equal to the height of the flagstaff
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