A pair of parallel lines is intersected by a transversal such that ∠1 and ∠2 form a pair of interior angles on the same side of the transversal. If m∠1 = 65°, what is the measure of ∠2?
115°
Step 1: Recall the property of **co-interior angles**.
When two parallel lines are cut by a transversal, the sum of co-interior angles on the same side of the transversal is **180°**.
Step 2: Apply the formula:
\[ \angle 1 + \angle 2 = 180^\circ \] \[ 65^\circ + \angle 2 = 180^\circ \] \[ \angle 2 = 180^\circ - 65^\circ = 115^\circ \] Thus, the correct answer is
115°.
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