A pair of parallel lines is intersected by a transversal such that ∠1 and ∠2 form a pair of interior angles on the same side of the transversal. If m∠1 = 65°, what is the measure of ∠2?
115°
Step 1: Recall the property of **co-interior angles**.
When two parallel lines are cut by a transversal, the sum of co-interior angles on the same side of the transversal is **180°**.
Step 2: Apply the formula:
\[ \angle 1 + \angle 2 = 180^\circ \] \[ 65^\circ + \angle 2 = 180^\circ \] \[ \angle 2 = 180^\circ - 65^\circ = 115^\circ \] Thus, the correct answer is
115°.
Important Questions from Co-ordinate Geometry
The graphs of the linear equations 4x - 2y = 10 and 4x + ky = 2 intersect at a point (a, 4). The value of k is equal to:
The area (in sq. units) of the triangle formed by the graphs of 8x + 3y = 24, 2x + 8 = y and the x-axis is:
What is the area (in unit squares) of the triangle enclosed by the graphs of 2x + 5y = 12, x + y = 3 and the x-axis?
The graphs of the equations 3x - 20y - 2 = 0 and 11x - 5y + 61 = 0 intersect at P(a, b). What is the value of (a 2+ b 2- ab)/(a 2- b 2+ ab)?
The graphs of the linear equations 3x - 2y = 8 and 4x + 3y = 5 intersect at the point P(α, β). What is the value of (2 α - β)?
