A man walks at 5/6 of his usual speed and reaches his destination 10 minutes late. What is the usual time (in minutes) taken?
50
For a fixed distance, time is inversely proportional to speed. If the speed becomes \(\frac{5}{6}\) of the usual speed, the time becomes \(\frac{6}{5}\) of the usual time T.
Extra time taken = \(\frac{6}{5}T - T = \frac{T}{5}\).
This extra time equals 10 minutes, so \(\frac{T}{5} = 10\) and T = 50 minutes.
Check: at the reduced speed the time is \(\frac{6}{5} \times 50 = 60\) minutes, which is 60 – 50 = 10 minutes more than the usual time, as stated.
Hence, 50.
Important Questions from Partial Speed
A train having length 210 metres takes 25 seconds to cross a 540 metres long bridge. How much time will the train take to cross a 630 metres long bridge?
A person X from a place A and another person Y from a place B set out at the same time to walk towards each other. The places are separated by a distance of 15 km. X walks with a uniform speed of 1.5 km / hr and Y walks with a uniform speed of 1 km / hr in the first hour, with a uniform speed of 1.25 km / hr in the second hour and with a uniform speed of 1.5 km / hr in the third hour and so on.
Which of the following is / are correct?
1. They take 5 hours to meet.
2. They meet midway between A and B.
Select the correct answer using the code given below:
The speed of a train is 120 kmph. What is the distance covered by it in 15 minutes?
I walk a certain distance and ride back taking a total time of 37 minutes. I could walk both ways in 55 minutes. How long would it take me to ride both ways ?
Karan had covered two third of a certain distance when his car had a breakdown. He parked it and covered the remaining distance on foot. His time of travel on foot was 9 times his time of travel on car. What is the ratio of his walking speed with respect to his car’s speed?
