This problem asks us to find the ratio between the number of chairs and the number of tables bought, given the total cost, the total number of items, and the individual costs of a table and a chair.
Let's define the variables:
From the question, we know:
We need to solve these two equations simultaneously.
From equation (1), we can express $t$ in terms of $c$:
$t = 12 - c$Now, substitute this expression for $t$ into equation (2):
$50(12 - c) + 40c = 500$Let's simplify and solve for $c$:
$600 - 50c + 40c = 500$ $600 - 10c = 500$Rearrange the equation to isolate the term with $c$:
$600 - 500 = 10c$ $100 = 10c$Divide by 10 to find the value of $c$:
$c = \frac{100}{10}$ $c = 10$So, the number of chairs purchased is 10.
Now, use equation (1) to find the number of tables ($t$):
$t = 12 - c$ $t = 12 - 10$ $t = 2$Therefore, the number of tables purchased is 2.
The question asks for the ratio of the numbers of the chairs and tables purchased. This means we need to find the ratio $c:t$.
We found $c = 10$ and $t = 2$.
The ratio is:
$c:t = 10:2$To simplify the ratio, divide both numbers by their greatest common divisor, which is 2:
$\frac{10}{2}:\frac{2}{2} = 5:1$The ratio of the numbers of the chairs and tables purchased is $5:1$.
In a mixture of 156 litres, the ratio of milk and water is 7 : 6. How much water should be added to make the ratio 14 : 13?
If the ratio of the first to second number is 3 : 4 and that of the second to the third number is 8 : 5, and sum of three numbers is 190 then the third number is:
The third proportional to 9 and 15 is:
The average age of 3 persons is 30 years.If their ages are in the ratio of 3 : 5 : 7 respectively, then the age of the eldest person is:
The income of A and B are in the ratio 5 : 3. The expenses of A, B and C are in the ratio of 8 : 5 : 2. If C spends 2000 and B saves ₹ 700, then A saves: