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Question

A girl of weight 440 N climbs up a rope through a height of 7 m in 20 s. The power expended by the girl is:

This question was previously asked in
RRB ALP 2018 CBT 2 Fitter Question Paper (21-Jan-2019) (Shift 3)
The correct answer is

154 W

Understanding Power Expended in Climbing

This physics problem asks us to calculate the power expended by a girl climbing a rope. Power is the rate at which work is done. In this case, the work done is against the force of gravity as the girl increases her height.

Identifying Given Information

We are given the following information:

  • Weight of the girl (which is the force she exerts against gravity): \(F = 440 \text{ N}\)
  • Height climbed (the distance): \(d = 7 \text{ m}\)
  • Time taken to climb: \(t = 20 \text{ s}\)

Calculating Work Done Against Gravity

The work done (\(W\)) when moving against a constant force over a distance is given by the formula:

\[W = \text{Force} \times \text{Distance}\]

In this scenario, the force is the girl's weight, and the distance is the height she climbs. So, the work done is:

\[W = F \times d\]

Substituting the given values:

\[W = 440 \text{ N} \times 7 \text{ m}\]

\[W = 3080 \text{ Joules}\]

The work done by the girl in climbing the rope is 3080 Joules.

Calculating Power Expended

Power (\(P\)) is the rate at which work is done. It is calculated using the formula:

\[P = \frac{\text{Work done}}{\text{Time taken}}\]

Using the work done we just calculated and the time taken:

\[P = \frac{W}{t}\]

Substituting the values:

\[P = \frac{3080 \text{ J}}{20 \text{ s}}\]

\[P = 154 \text{ J/s}\]

Since 1 Joule per second is equal to 1 Watt (W), the power expended by the girl is:

\[P = 154 \text{ W}\]

Final Power Calculation

The power expended by the girl climbing the rope is 154 W.

Revision Table: Work, Energy, and Power Concepts

Concept Definition Formula SI Unit
Work (W) Energy transferred by a force acting over a distance. \(W = F \times d \times \cos(\theta)\) (where \(\theta\) is angle between force and displacement) Joule (J)
Potential Energy (Gravitational) (PE) Energy stored by an object due to its position in a gravitational field. \(PE = mgh\) or \(PE = \text{weight} \times \text{height}\) Joule (J)
Power (P) The rate at which work is done or energy is transferred. \(P = \frac{W}{t}\) or \(P = F \times v\) (where v is velocity) Watt (W)

Additional Information: Climbing and Power

When a person climbs vertically, they are doing work against gravity. The force they exert is equal to their weight (assuming constant velocity or average power). The work done results in an increase in the person's gravitational potential energy. The power calculated here represents the useful power output against gravity. The total power generated by the girl would be higher, including power expended against air resistance and internal biological inefficiencies.

The unit of power, the Watt (W), is named after James Watt, a Scottish inventor, mechanical engineer, and chemist.

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