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Question

A cuboid has length 10 cm, breadth 5 cm and height 2 cm. What is its surface area?

This question was previously asked in
RRB NTPC 2024 CBT 1 Question Paper (28-Aug-2025) (Shift 3)
The correct answer is
$160 \text{ cm}^2$

Cuboid Surface Area Calculation

We need to find the surface area of a cuboid with the given dimensions.

  • Length ($l$): 10 cm
  • Breadth ($b$): 5 cm
  • Height ($h$): 2 cm

Surface Area Formula

The formula for the total surface area of a cuboid is:

Surface Area = $2(lb + bh + hl)$

Step-by-Step Calculation

Substitute the given values into the formula:

Surface Area = $2 \times ((10 \text{ cm} \times 5 \text{ cm}) + (5 \text{ cm} \times 2 \text{ cm}) + (2 \text{ cm} \times 10 \text{ cm}))$

First, calculate the products inside the parentheses:

  • $l \times b = 10 \times 5 = 50 \text{ cm}^2$
  • $b \times h = 5 \times 2 = 10 \text{ cm}^2$
  • $h \times l = 2 \times 10 = 20 \text{ cm}^2$

Now, add these values:

Surface Area = $2 \times (50 \text{ cm}^2 + 10 \text{ cm}^2 + 20 \text{ cm}^2)$

Surface Area = $2 \times (80 \text{ cm}^2)$

Finally, perform the multiplication:

Surface Area = $160 \text{ cm}^2$

Final Answer

The surface area of the cuboid is $160 \text{ cm}^2$.

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Important Questions from 3-D Mensuration

  1. Find the surface area of a sphere whose diameter is equal to 98 cm.
  2. A conical vessel has base radius 31 cm and height 45 cm. Water is poured into the vessel until it is $\frac{2}{3}$ full. Find the volume (in cm³) of water in the vessel.
  3. A solid metallic sphere of radius 10 cm is melted and recast into 125 identical spheres. What is the ratio of the surface area of the original sphere to the total surface area of 6 smaller spheres so formed?
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