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Question

A copper wire has a resistance of 3 Ω and carries a current of 4 A. What is the power loss in the wire due to heating?

This question was previously asked in
RRB ALP 2025 CBT 2 Wiremen Question Paper (28-Jul-2026) (Shift 2)
The correct answer is

48 W

To determine the power loss in the copper wire due to heating, we use the formula for electrical power dissipated as heat through a resistor. The formula is given by:

\(P = I^2 R\)

where:

  • \(P\) is the power loss in watts (W).
  • \(I\) is the current passing through the wire in amperes (A).
  • \(R\) is the resistance of the wire in ohms (Ω).

From the question, we are given:

  • Resistance \((R) = 3 \, \Omega\)
  • Current \((I) = 4 \, \text{A}\)

Substituting these values into the formula, we get:

\(P = (4)^2 \times 3\)

Calculating further:

  • \((4)^2 = 16\)
  • Thus, \(P = 16 \times 3 = 48 \, \text{W}\)

Therefore, the power loss in the wire due to heating is 48 W.

The correct option is 48 W.

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