A copper wire has a resistance of 3 Ω and carries a current of 4 A. What is the power loss in the wire due to heating?
48 W
To determine the power loss in the copper wire due to heating, we use the formula for electrical power dissipated as heat through a resistor. The formula is given by:
\(P = I^2 R\)
where:
From the question, we are given:
Substituting these values into the formula, we get:
\(P = (4)^2 \times 3\)
Calculating further:
Therefore, the power loss in the wire due to heating is 48 W.
The correct option is 48 W.
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