This problem involves calculating the cross-sectional area ('A') of a confined aquifer perpendicular to groundwater flow, utilizing Darcy's Law.
Darcy's Law describes the rate of flow ($Q$) through a porous medium. The fundamental equation is:
$ Q = k \cdot A \cdot i $
Where:
To find the unknown area 'A', we rearrange Darcy's Law formula:
$ A = \frac{Q}{k \cdot i} $
The problem provides the following values:
Substitute these known values into the rearranged formula:
$ A = \frac{250 \text{ m}^3/\text{day}}{(2 \text{ m/day}) \times (0.005)} $
First, calculate the product of permeability and gradient in the denominator:
$ k \times i = 2 \times 0.005 = 0.01 $
Now, perform the division to find the area:
$ A = \frac{250}{0.01} $
$ A = 25000 \text{ m}^2 $
The calculated cross-sectional area ('A') of the confined aquifer is 25000 m$^2$.