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Question

A complex that possess 5D ground term symbol for its metal ion is :

This question was previously asked in
MH SET 2021 Paper 2 Mathematical Science Question Paper (26-Sep-2021)
The correct answer is

[Cr(H2O)6]2+

A 5D term has spin multiplicity 5 (four unpaired electrons, S = 2) and L = 2. It is the ground term of d4 and d6 ions, and a complex keeps this quintet ground state only when the ligand field is weak enough for the ion to stay high spin; in an octahedral field the 5D term becomes 5Eg (d4) or 5T2g (d6).

Step 1 — [Cr(H2O)6]2+: Cr(II) is d4; water is a weak-field ligand, so the complex is high spin, t2g3eg1, with four unpaired electrons and a ground state derived from 5D.

Step 2 — [Mn(CN)6]3– is d4 but strong-field cyanide makes it low spin, t2g4, with two unpaired electrons and a triplet (3T1g) ground state. [Fe(CN)6]4– is low-spin d6, t2g6, diamagnetic with a 1A1g ground state. [Co(H2O)6]2+ is high-spin d7, whose ground term is 4F, not a D term.

[Cr(H2O)6]2+ option is correct.

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