A can do a piece of work in 16 days. B is 60% more efficient than A. How much time will A and B together take to finish the work?
\(6\dfrac{2}{13}\) days
A's 1 day work = 1/16.
B is 60% more efficient than A, so B's 1 day work = 1.6 × (1/16) = 1/10.
Combined 1 day work = 1/16 + 1/10 = (5 + 8)/80 = 13/80.
Time taken together = 80/13 = 6 2/13 days.
Hence, A and B together will finish the work in 6 2/13 days.
Important Questions from Work Efficiency
A man completes 7/8 of a job in 21 days. How many more days will it take him to finish the job if quantum of work further increased by 50%?
24 men and 12 women can do a piece of work in 30 days. In how many days can 12 men and 24 women do the same piece of work?
A and B together can do a piece of work in 4 days, B and C can do it in 6 days, A and C can do it in 8 days. Then A, B and C together can do the same work in :-
A can complete 50% of a work in 9 days and B can do 25% of the work in 9 days, if they work alone. If they work together then how much work (in percentage) can be completed in 6 days?
A is thrice as good a workman as B. C alone takes 48 days to paint a house. All three A, B and C working together take 16 days to paint the house. It will take how many days for A alone to paint the house?
