The problem asks for the final price of a Rs. 1000 item after applying two successive discounts: 20% and then 10%. We need to calculate the price step-by-step.
The initial price of the item is Rs. 1000.
The first discount is 20%. The amount of the first discount is:
$Discount_1$ = 20% of Rs. 1000
$ \text{Discount\_1} = \frac{20}{100} \times 1000 = 0.20 \times 1000 = 200 $
The price after the first discount is:
$ \text{Price\_1} = \text{Original Price} - \text{Discount\_1} $
$ \text{Price\_1} = 1000 - 200 = 800 $
So, after the first 20% discount, the price becomes Rs. 800.
The second discount of 10% is applied to the price obtained after the first discount (Rs. 800).
The amount of the second discount is:
$Discount_2$ = 10% of Rs. 800
$ \text{Discount\_2} = \frac{10}{100} \times 800 = 0.10 \times 800 = 80 $
The final price paid by the buyer is:
$ \text{Final Price} = \text{Price\_1} - \text{Discount\_2} $
$ \text{Final Price} = 800 - 80 = 720 $
We can also calculate the final price directly:
$ \text{Final Price} = \text{Original Price} \times (1 - \text{Discount Rate 1}) \times (1 - \text{Discount Rate 2}) $
$ \text{Final Price} = 1000 \times (1 - 0.20) \times (1 - 0.10) $
$ \text{Final Price} = 1000 \times (0.80) \times (0.90) $
$ \text{Final Price} = 1000 \times 0.72 $
$ \text{Final Price} = 720 $
The final price paid for the item after successive discounts of 20% and 10% is Rs. 720.
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