The problem asks for the speed at which a boy approaches a pole while winding a rope of length $l$ around it. The radius of the pole is $r$, and each round takes $10\text{ s}$.
When the boy completes one full revolution ($2\pi$ radians) around the pole, the amount of rope that gets wound onto the pole is equal to the circumference of the pole.
Length wound in one round = $ 2\pi r $
The time taken for one round is given as $10\text{ s}$. The rate at which the rope winds onto the pole is the length wound divided by the time taken.
Rate of winding = $ \frac{2\pi r}{10\text{ s}} $
Simplifying this expression gives:
Rate of winding = $ \frac{\pi r}{5} \text{ units/s} $
As the rope winds around the pole, the length of the *unwound* portion of the rope decreases. This decrease in unwound length directly corresponds to the boy moving closer to the pole. Therefore, the speed at which the boy approaches the pole is equal to the rate at which the rope winds up.
Speed of approach = Rate of winding = $ \frac{\pi r}{5} $
With a certain set of diameters, a tractor's front wheels make 2 revolutions (revs) for every 1 revolution of the rear wheels. The effect of changing wheel diameter(s) is shown in the following plot. 
In this context, which of the following statements is CORRECT?
A car covers 4 successive stretches of 3 km each at speed of 10 kmph, 20 kmph, 30 kmph and 60 kmph respectively. The average speed of the car for the entire journey is: