A body weighs W1 at a place where the acceleration due to gravity is g1. At another place, its weight becomes 5/3 W1. Assuming the mass of the body remains constant, what is the ratio g2:g1?
5 : 3
Weight is \(W = mg\); with mass constant, weight is directly proportional to g.
\(\frac{g_2}{g_1} = \frac{W_2}{W_1} = \frac{\frac{5}{3}W_1}{W_1} = \frac{5}{3}\)
So \(g_2 : g_1 = 5 : 3\).
Hence, the answer is 5 : 3.
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