The problem asks for the bending moment at the fixed (left) end of a cantilever beam.
Beam Setup:
Load Details:
The bending moment at the fixed end of a cantilever beam is caused by the loads applied to the free portion of the beam. The moment is calculated as the product of the load and its perpendicular distance from the fixed end.
Let the fixed end be point A (at 0m). The load $P$ is applied at a distance $x$ from the fixed end.
Distance of the load from the fixed end ($x$): 4m
Load ($P$): 25 kN
The bending moment ($M_A$) at the fixed end (A) is calculated using the formula:
$ M_A = P \times x $
Substitute the values:
$ M_A = 25 \, \text{kN} \times 4 \, \text{m} $
$ M_A = 100 \, \text{kNm} $
The bending moment at the left end (fixed end) is 100 kNm. The downward load typically causes a hogging moment (often considered negative), but the magnitude is 100 kNm.
A simply supported RCC beam of cross section $0.4 \text{ m} \times 0.6 \text{ m}$ covers a span of $8 \text{ m}$. It is subjected to a uniformly distributed load of $30 \text{ kN/m}$. If the unit weight of concrete is $24 \text{ kN/m}^3$, the tensile stress (in $N/mm^2$, rounded off to two decimal places) at the bottom of the beam at mid-span is______
A rectangular beam section of size 300 mm (width) X 500 mm (depth) is loaded with a shear force of 600 kN. The maximum shear stress on the section in N/mm² is ___________
A simply supported beam AB has a clear span of 7 meter. The bending moment diagram (BMD) of the beam due to a single concentrated load is shown in the figure below.
The magnitude of the concentrated load in kN is __________.