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Question

A $10\text{ km}$ long and $1\text{ m}$ wide sheet of thickness $0.1\text{ mm}$ is rolled along the length parallel to its width forming a perfectly compact solid cylinder. The diameter of the cylinder in meter is approximately

The correct answer is
$2/\pi^{1/2}$

Calculate Cylinder Diameter: Sheet Rolled into Solid Cylinder

This solution determines the diameter of a solid cylinder formed by rolling a sheet, using the principle of volume conservation.

Given Sheet Dimensions

  • Length: $10 \text{ km} = 10,000 \text{ m}$
  • Width: $1 \text{ m}$
  • Thickness: $0.1 \text{ mm} = 10^{-4} \text{ m}$

Calculate Sheet Volume

First, find the volume ($V$) of the sheet material. The volume of the resulting solid cylinder must be equal to this.

$ V = \text{Length} \times \text{Width} \times \text{Thickness} $

$ V = (10,000 \text{ m}) \times (1 \text{ m}) \times (10^{-4} \text{ m}) $

$ V = 1 \text{ m}^3 $

Cylinder Volume and Diameter Relationship

The volume of a cylinder is given by the formula $ V = \pi r^2 h $. Using the diameter $d$ (where $r = d/2$), the formula is:

$ V = \pi \left(\frac{d}{2}\right)^2 h = \frac{\pi d^2 h}{4} $

For the cylinder formed, we assume the sheet's width ($W$) becomes the cylinder's height ($h$):

$ h = W = 1 \text{ m} $

Solving for Cylinder Diameter

Equate the calculated sheet volume ($1 \text{ m}^3$) to the cylinder volume formula and solve for the diameter $d$:

$ V_{\text{sheet}} = V_{\text{cylinder}} $

$ 1 \text{ m}^3 = \frac{\pi d^2 h}{4} $

Substitute the value $ h = 1 \text{ m} $ into the equation:

$ 1 = \frac{\pi d^2 (1)}{4} $

Rearrange to solve for $d^2$:

$ \pi d^2 = 4 $

$ d^2 = \frac{4}{\pi} $

Take the square root of both sides to find the diameter:

$ d = \sqrt{\frac{4}{\pi}} = \frac{2}{\sqrt{\pi}} $

$ d = \frac{2}{\pi^{1/2}} \text{ m} $

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Important Questions from Mensuration 3D (Notes)

  1. The height of a cylinder is 14cm and its curved surface area is 264cm². The volume of the cyclinder (in cm³) is:
    ($\pi=\frac{22}{7}$)
  2. A cylindrical rod has an outer curved surface area of \(7500 \text{ cm}^2\). If the length of the rod is 92 cm, then the outer radius (in cm) of the rod, rounded off to two places of decimal, is:
    \(\left(\text{Take } \pi = \frac{22}{7}\right)\)
  3. A number of 512 identical small spheres are cast from a sphere of radius 40 cm, with the total volume of the small spheres being equal to the volume of the larger sphere. The diameter (in cm) of each of the small spheres is:
  4. There is a wooden block in the form of a cube whose each side is 8 meters long. 

    The maximum possible number of cylinders with a diameter of 1 meter and a height of 4 meters were cut from this block. The cylinders are to be painted at the rate of ₹14 per square meter.
     

    What is the total amount (in ₹) needed to paint all the cylinders if we paint the entire surface of each cylinder? (Take $\pi = \frac{22}{7}$)

  5. If the lateral surface area of a cylinder is $140.1 \text{ cm}^2$ and its height is $3 \text{ cm}$, then find its volume. (Use $\pi = 3.14$ and round off to two decimal places.)
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