\(\frac{8^2}{4^3}\) is equal to :
1
Express 8 and 4 as powers of 2: \(8 = 2^3\) and \(4 = 2^2\).
So \(8^2 = (2^3)^2 = 2^6\) and \(4^3 = (2^2)^3 = 2^6\).
Therefore, \(\frac{8^2}{4^3} = \frac{2^6}{2^6} = 2^0 = 1\).
Hence, \(\frac{8^2}{4^3}\) is equal to 1.
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