53
We need to find the number of students taking all three subjects: Chemistry (C), Physics (P), and Mathematics (M).
We are given:
The Principle of Inclusion-Exclusion for three sets states:
$|C \cup P \cup M| = |C| + |P| + |M| - |C \cap P| - |C \cap M| - |P \cap M| + |C \cap P \cap M|$Let $x$ represent the number of students taking all three subjects, i.e., $x = |C \cap P \cap M|$. Plugging the given values into the formula:
$500 = 329 + 186 + 295 - 83 - 217 - 63 + x$First, sum the enrollments in individual subjects:
$329 + 186 + 295 = 810$Next, sum the enrollments in pairs of subjects:
$83 + 217 + 63 = 363$Substitute these sums back into the equation:
$500 = 810 - 363 + x$ $500 = 447 + x$Solve for $x$:
$x = 500 - 447$ $x = 53$Therefore, 53 students are taking all three subjects.
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