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Question

$(41^{43} + 43^{43})$ is divisible by:

This question was previously asked in
RRB NTPC 2019 CBT 1 Question Paper (8-Mar-2021) (Shift 2)
The correct answer is
84

Divisibility of \(41^{43} + 43^{43}\)

We need to find a number that divides the expression \(41^{43} + 43^{43}\).

Key Divisibility Rule

Recall the algebraic identity: If \(n\) is an odd integer, then \(a^n + b^n\) is always divisible by \(a+b\).

Applying the Rule

In the given expression, \(41^{43} + 43^{43}\):

  • \(a = 41\)
  • \(b = 43\)
  • \(n = 43\)

Since the exponent \(n=43\) is an odd number, the expression \(41^{43} + 43^{43}\) is divisible by the sum of the bases, \(a+b\).

Calculation

Calculate the sum \(a+b\):

$ a+b = 41 + 43 = 84 $

Conclusion

Therefore, \(41^{43} + 43^{43}\) is divisible by 84.

Comparing this result with the given options, we find that 84 is one of the options.

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