40% persons read newspaper X and 50% persons read newspaper Y. 10% persons read both newspapers. How many persons do not read any of the newspapers ?
20%
This problem involves calculating the percentage of people who do not read any newspapers, given the percentages of people who read specific newspapers and those who read both.
We are provided with the following details:
To find the percentage of people who read at least one newspaper (either X or Y or both), we use the principle of inclusion-exclusion from set theory. The formula is:
$P(X \cup Y) = P(X) + P(Y) - P(X \cap Y)$
Where:
First, let's calculate the percentage of people who read at least one newspaper:
$P(X \cup Y) = 40\% + 50\% - 10\%$
$P(X \cup Y) = 90\% - 10\%$
$P(X \cup Y) = 80\%$
The total percentage of people surveyed is 100%. The percentage of people who do not read any newspaper is the total percentage minus the percentage of people who read at least one newspaper.
Percentage of persons who do not read any newspaper = $100\% - P(X \cup Y)$
Now, substitute the value we found for $P(X \cup Y)$:
Percentage of persons who do not read any newspaper = $100\% - 80\%$
Percentage of persons who do not read any newspaper = $20\%$
Therefore, 20% of the persons surveyed do not read either newspaper X or newspaper Y.
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