36 men and 48 women can do a certain work in one day whereas 6 men and 12 women can do it in 5 days. The number of women required to do the same work in 8 days is :
15
Let the efficiency of a man be x and the efficiency of a woman be y, then
According to the question
(36x + 48y) × 1 = (6x + 12y) × 5
⇒ 36x + 48y = 30x + 60y
⇒ 36x – 30x = 60y – 48y
⇒ 6x = 12y
x : y = 2 : 1
Total work = (6x + 12y) × 5 = (6 × 2 + 12 × 1) × 5 = (12 + 12) × 5 = 24 × 5 = 120
Let the number of women required to complete the same work in 8 days be n, then
n × 8 = 120
⇒ n = 120/8 = 15
Therefore, 15 women will be required to complete the same work in 8 days.Important Questions from Work Efficiency
Five men and 2 boys can do in 30 days as much work as 7 men and 10 boys can do in 15 days. How many boys should join 40 men to do the same work in 4 days?
A man completes 7/8 of a job in 21 days. How many more days will it take him to finish the job if quantum of work further increased by 50%?
24 men and 12 women can do a piece of work in 30 days. In how many days can 12 men and 24 women do the same piece of work?
A and B together can do a piece of work in 4 days, B and C can do it in 6 days, A and C can do it in 8 days. Then A, B and C together can do the same work in :-
A can complete 50% of a work in 9 days and B can do 25% of the work in 9 days, if they work alone. If they work together then how much work (in percentage) can be completed in 6 days?
