36 men and 48 women can do a certain work in one day whereas 6 men and 12 women can do it in 5 days. The number of women required to do the same work in 8 days is :
15
Let the efficiency of a man be x and the efficiency of a woman be y, then
According to the question
(36x + 48y) × 1 = (6x + 12y) × 5
⇒ 36x + 48y = 30x + 60y
⇒ 36x – 30x = 60y – 48y
⇒ 6x = 12y
x : y = 2 : 1
Total work = (6x + 12y) × 5 = (6 × 2 + 12 × 1) × 5 = (12 + 12) × 5 = 24 × 5 = 120
Let the number of women required to complete the same work in 8 days be n, then
n × 8 = 120
⇒ n = 120/8 = 15
Therefore, 15 women will be required to complete the same work in 8 days.Important Questions from Work Efficiency
A and B together can complete a certain work in 20 days whereas B and C together can complete it in 24 days. If A is twice as good a workman as C, then in what time will B alone do 40% of the same work?
14 men can complete a work in 15 days. If 21 men are employed, then in how many days will they complete the same work?
A can do a certain work in 15 days, while B can do the same work in 21 days. If they work together, then in how many days will the same work be completed?
To do a certain work, A and B work on alternate days with B beginning the work on the first day. A alone can complete the same work in 24 days. If the work gets completed in \(11 \frac{1}{3}\) days, then B alone can complete \(\rm \frac{7}{9}^{th}\) part of the original work in:
Two men and 7 women can complete a work in 28 days whereas 6 men and 16 women can do the same work in 11 days. In how many days can 7 men complete the same work?
