14 workers working 16 hours per day can demolish a building in 81 days. In how many days 18 workers working 24 hours per day can demolish the same building?
42 days
This question involves a common type of problem where the amount of work done is related to the number of workers, the hours they work per day, and the number of days they take to complete the work. The core idea is that the total amount of work required to demolish the building is constant.
We can think of the total work as the product of the number of workers, the number of days, and the number of hours worked per day, assuming each worker works at the same rate. This relationship can be expressed as:
\( \text{Work} = \text{Number of Workers} \times \text{Number of Days} \times \text{Hours per Day} \)
Since the work (demolishing the same building) is the same in both scenarios given in the question, we can set up an equation:
\( (\text{Workers}_1 \times \text{Days}_1 \times \text{Hours}_1) = (\text{Workers}_2 \times \text{Days}_2 \times \text{Hours}_2) \)
From the question, we have the following information:
Let's plug these values into our equation:
\( 14 \times 81 \times 16 = 18 \times \text{Days}_2 \times 24 \)
Our goal is to find \(\text{Days}_2\). We can rearrange the equation to solve for \(\text{Days}_2\):
\( \text{Days}_2 = \frac{14 \times 81 \times 16}{18 \times 24} \)
Now, let's calculate the value:
\( \text{Days}_2 = \frac{18144}{432} \)
Let's perform the division:
\( \frac{18144}{432} = 42 \)
Alternatively, we can simplify the fraction directly:
\( \text{Days}_2 = \frac{14 \times 81 \times 16}{18 \times 24} \)
Both methods give the same result.
Therefore, 18 workers working 24 hours per day can demolish the same building in 42 days.
| Factor | Relationship to Work | How it Affects Time (Days) |
|---|---|---|
| Number of Workers | Directly Proportional | More workers mean fewer days (Inverse relationship) |
| Hours per Day | Directly Proportional | More hours per day mean fewer days (Inverse relationship) |
| Number of Days | Directly Proportional | More days mean less work done per day per worker (Used to measure total time) |
| Total Work | Constant (in this problem) | Remains the same for both scenarios |
In problems like these, the 'work rate' of a single worker is often assumed to be constant. The total work rate of a group of workers is the sum of their individual rates. When workers work more hours per day, their effective contribution per day increases.
The formula \(M \times D \times H = \text{Constant Work}\) is based on the idea that the total 'worker-hours' (or 'worker-day-hours') needed for a specific task is fixed. As you increase any factor on the left side (Workers, Days, Hours), you generally need to decrease another factor to keep the total constant, assuming the total work remains the same.
Key concepts to remember:
A and B working together can complete a job in 30 days. The ratio of their efficiencies is 3 : 2. In how many days can the faster person complete the job?
A takes 15 days to complete \(\frac{5}{7} \) of a work. With the help of B, they finish the whole work in 12 days. In how many days, B alone will complete the same work
A alone can complete a work in 14 days and B alone can complete the same work in 21 days. A and B start the work together but A leaves the work after 4 days of the starting of work. In how many days B will complete the remaining work?
For completing a certain work, A is 50% less efficient than B and B is 50% more efficient than C. Working together A, B and C can complete the work in 48 days. A alone can complete the same work in:
30 persons can do a piece of work in 24 days. How many more persons are required to complete the work in 20 days?