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Question

Which statement is true for electrochemical series?

The correct answer is
(Ag+ /Ag) is the less strongly reducing as compared to (Zn2+/ Zn) and (Ca2+/Ca) is most reducing

The electrochemical series is a list of chemical species arranged in order of their standard electrode potentials. This series is crucial for understanding the relative tendencies of species to be oxidized or reduced, and therefore, their relative strengths as reducing or oxidizing agents.

Understanding Reducing Ability and Electrochemical Series

In the electrochemical series, the standard reduction potential ($E^{\circ}$) for different redox couples is measured relative to the standard hydrogen electrode (SHE). The reduction potential indicates the tendency of a species to gain electrons and be reduced.

  • A more positive (or less negative) standard reduction potential ($E^{\circ}$) indicates a greater tendency for reduction, meaning the oxidized form is a stronger oxidizing agent.
  • A more negative (or less positive) standard reduction potential ($E^{\circ}$) indicates a greater tendency for oxidation of the reduced form, meaning the reduced form is a stronger reducing agent.

Therefore, a lower (more negative) standard reduction potential corresponds to a stronger reducing agent (the element or the reduced form). A higher (more positive) standard reduction potential corresponds to a weaker reducing agent.

Comparing Reducing Ability of Ag, Zn, and Ca

We need to compare the reducing ability of Ag, Zn, and Ca based on their standard reduction potentials for the given redox couples: (Ag+/Ag), (Zn2+/Zn), and (Ca2+/Ca). Let's look up the approximate standard reduction potentials:

  • For (Ag+/Ag): $E^{\circ} \approx +0.80$ V
  • For (Zn2+/Zn): $E^{\circ} \approx -0.76$ V
  • For (Ca2+/Ca): $E^{\circ} \approx -2.87$ V

Now, let's compare these standard reduction potentials:

$-2.87\text{ V (Ca)} < -0.76\text{ V (Zn)} < +0.80\text{ V (Ag)}$

Since a lower standard reduction potential indicates a stronger reducing agent, the order of reducing ability is:

Ca > Zn > Ag

This means Ca is the strongest reducing agent among these three, followed by Zn, and Ag is the weakest reducing agent.

Analyzing the Given Statements

Let's evaluate each statement based on our findings:

  1. (Ag+/Ag) is the more strongly reducing as compared to (Zn2+/Zn) and (Ca2+/Ca) is least reducing

    This statement says Ag is more reducing than Zn, which is false (Ag is weaker). It also says Ca is least reducing, which is false (Ca is strongest).

  2. (Ag+/Ag) is the less strongly reducing as compared to (Zn2+/ Zn) and (Ca2+/Ca) is most reducing

    This statement says Ag is less reducing than Zn, which is true. It also says Ca is most reducing, which is true among these three. This statement aligns with our analysis.

  3. (Zn2+/Zn) is more strongly reducing than (Ca2+/Ca) and (Ag+/Ag) is most  strongly reducing

    This statement says Zn is more reducing than Ca, which is false (Zn is weaker). It also says Ag is most reducing, which is false (Ag is weakest).

  4. All redox couples have similar reducing ability

    This statement is false. The standard reduction potentials are significantly different, indicating different reducing abilities.

Based on the comparison of standard reduction potentials and the definition of reducing ability, the statement that (Ag+/Ag) is less strongly reducing than (Zn2+/Zn) and (Ca2+/Ca) is the most reducing among these three is correct.

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Important Questions from Electrochemistry

  1. At $298 \, K$, given the standard electrode potentials: $E^\circ_{Cu^{2+}/Cu} = 0.34 \, V$, $E^\circ_{Zn^{2+}/Zn} = -0.76 \, V$, $E^\circ_{Fe^{2+}/Fe} = -0.44 \, V$, and $E^\circ_{Ag^{+}/Ag} = 0.80 \, V$.
    Based on these values, which of the following reactions is NOT expected to occur spontaneously under standard conditions?
  2. You are given three metals 'X', 'Y' and 'Z'. Metal 'X' is found to react with an aqueous solution of both YSO 4and ZSO 4whereas metal 'Z' is found to react only with aqueous solution of YSO 4. Based on these observations, select the correct statement from the following.

  3. If the overpotential of an electrolysis process is increased from 0.5 V to 0.6 V, then the ratio of current densities (In \(\frac{\int0.6 }{\int0.5}\)) of the electrolysis will be equal to (given transfer co - efficient = 0.5)

  4. The chemical potential (μ) of a 2 molar Na2SO4 solution is expressed in terms of mean ionic activity co - efficient (γ±) as

  5. The E°(M+/M) of the cell, SHE||MX|M can be obtained from the plot of (E cell is the cell potential and m is the molality of ideal dilute solution of MX)

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