You are given three metals 'X', 'Y' and 'Z'. Metal 'X' is found to react with an aqueous solution of both YSO 4and ZSO 4whereas metal 'Z' is found to react only with aqueous solution of YSO 4. Based on these observations, select the correct statement from the following.
Understanding Metal Reactivity and Solution Storage
This problem involves understanding the reactivity of metals and how it relates to storing chemical solutions in containers made of different metals. A metal will displace another metal from its salt solution if it is more reactive.
Determining the Reactivity Series
Let's analyze the given information to establish the reactivity order of metals X, Y, and Z.
- Metal 'X' reacts with aqueous YSO4. This implies that 'X' is more reactive than 'Y'. We can represent this as:
X > Y - Metal 'X' also reacts with aqueous ZSO4. This implies that 'X' is more reactive than 'Z'. We can represent this as:
X > Z - Metal 'Z' reacts only with aqueous YSO4. This implies that 'Z' is more reactive than 'Y'. We can represent this as:
Z > Y
Combining these observations, we can determine the reactivity order:
- Since X is more reactive than both Y and Z, X is the most reactive.
- Since Z reacts with YSO4, Z is more reactive than Y.
Therefore, the reactivity series is: X > Z > Y.
Analyzing Storage Compatibility
A solution of a metal salt can be safely stored in a container made of another metal only if the container metal is *less reactive* than the metal present in the solution. If the container metal is more reactive, it will react with the solution and displace the metal.
Evaluating the Options:
-
Option 1: Solution of YSO4 can be stored in a container made of 'Z'.
The solution contains metal Y. The container is made of metal Z. Since Z is more reactive than Y (Z > Y), metal Z will displace Y from the YSO4 solution. This container is not suitable. -
Option 2: Solution of ZSO4 can be stored in a container made of 'X'.
The solution contains metal Z. The container is made of metal X. Since X is more reactive than Z (X > Z), metal X will displace Z from the ZSO4 solution. This container is not suitable. -
Option 3: Solution of XSO4 can be stored in a container made of 'Y' as well as 'Z'.
Container made of 'Y': The solution contains metal X. The container is made of metal Y. Since X is more reactive than Y (X > Y), Y is less reactive than X. Therefore, Y will not displace X from XSO4. This container is suitable.
Container made of 'Z': The solution contains metal X. The container is made of metal Z. Since X is more reactive than Z (X > Z), Z is less reactive than X. Therefore, Z will not displace X from XSO4. This container is suitable.
Since both conditions are met, this statement is correct. -
Option 4: Solution of YSO4 can be stored in a container made of 'X' as well as 'Z'.
Container made of 'X': The solution contains metal Y. The container is made of metal X. Since X is more reactive than Y (X > Y), X will displace Y from YSO4. This container is not suitable. (We already know from Option 1 that Z is also unsuitable). Since the first part is false, the entire statement is incorrect.
Conclusion
Based on the reactivity series X > Z > Y, a solution of XSO4 can be stored in containers made of either Y or Z because both Y and Z are less reactive than X.
Important Questions from Electrochemistry
- At $298 \, K$, given the standard electrode potentials: $E^\circ_{Cu^{2+}/Cu} = 0.34 \, V$, $E^\circ_{Zn^{2+}/Zn} = -0.76 \, V$, $E^\circ_{Fe^{2+}/Fe} = -0.44 \, V$, and $E^\circ_{Ag^{+}/Ag} = 0.80 \, V$.
Based on these values, which of the following reactions is NOT expected to occur spontaneously under standard conditions? - Which of the following processes is required for extracting metal from cinnabar ore?
The mobility of a divalent cation in water is 8 × 10-8 m2 V-1 s-1. The effective radius of the ion is (viscosity of water = 1 cP : c = 1.6 × 10-19 C)
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If the overpotential of an electrolysis process is increased from 0.5 V to 0.6 V, then the ratio of current densities (In \(\frac{\int0.6 }{\int0.5}\)) of the electrolysis will be equal to (given transfer co - efficient = 0.5)
