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Question

Which one of the following statements is correct?

The correct answer is

The measurement of mass taken by a spring weighing balance is corrected at the place where the acceleration due to gravity is the same with the place where the spring balance is calibrated for

Understanding Spring Balance and Mass Measurement Accuracy

A spring balance is a device used to measure the force acting on an object. When used to measure the 'mass' of an object, it actually measures the object's weight. Weight is the force exerted on an object due to gravity, and it is calculated using the formula:

$$W = m \times g$$

where:

  • \(W\) is the weight
  • \(m\) is the mass of the object
  • \(g\) is the acceleration due to gravity

Mass is an intrinsic property of an object and remains constant regardless of its location. However, weight is a force that depends on the acceleration due to gravity (\(g\)), which varies slightly from place to place on Earth and significantly on other celestial bodies.

A spring balance works by measuring the extension of a spring under the load's weight. The scale on the spring balance is usually marked in units of mass (like kilograms or grams). This scale is calibrated at a specific location, meaning the markings correspond to mass values assuming a specific value of gravity (\(g_{calibration}\)) at that calibration site.

When an object of mass \(m\) is placed on a spring balance calibrated at a location with gravity \(g_{calibration}\), the spring extends due to its weight \(W = m \times g_{local}\), where \(g_{local}\) is the local acceleration due to gravity. The spring balance then displays a reading \(R\), which is essentially \(W / g_{calibration}\).

$$R = \frac{W}{g_{calibration}} = \frac{m \times g_{local}}{g_{calibration}}$$

For the reading \(R\) to be equal to the actual mass \(m\), the ratio \(g_{local} / g_{calibration}\) must be equal to 1. This happens only when \(g_{local} = g_{calibration}\).

Analyzing the Options for Spring Balance Accuracy

Let's evaluate each statement based on this understanding:

  • Option 1: The measurement of mass taken by spring weighing balance is correct at the place where the spring balance is calibrated for.

    This statement is partially correct. At the calibration location, \(g_{local} = g_{calibration}\), so the reading \(R = m \times (g_{calibration} / g_{calibration}) = m\). The measurement is indeed correct here. However, it might also be correct at other places where the acceleration due to gravity happens to be the same as the calibration location.

  • Option 2: The measurement of mass taken by a spring weighing balance is correct at all places.

    This statement is incorrect. Since the acceleration due to gravity (\(g\)) varies from place to place, the weight of an object (\(W = mg\)) also varies. A spring balance measures weight and assumes a fixed 'g' for its mass scale calibration. Therefore, its mass reading will not be accurate everywhere unless 'g' is constant everywhere, which it is not.

  • Option 3: The measurement of mass taken by a spring weighing balance is corrected at the place where the acceleration due to gravity is the same with the place where the spring balance is calibrated for.

    This statement is correct. As derived above, the mass reading \(R = m \times (g_{local} / g_{calibration})\). The reading \(R\) equals the actual mass \(m\) precisely when \(g_{local} = g_{calibration}\). This condition is met not only at the original calibration location but also at any other place where the local acceleration due to gravity is identical to that at the calibration location.

  • Option 4: A spring balance cannot be used to measure mass at any place.

    This statement is incorrect. While a spring balance fundamentally measures weight, it can be used to measure mass accurately under the specific condition mentioned in Option 3, and approximately in regions where the variation in 'g' is negligible for the required precision. Also, if the local gravity is known, the reading can be corrected to find the true mass.

Based on the analysis, Option 3 provides the most accurate description of when a spring balance measurement correctly represents the mass of an object.

Revision Table: Spring Balance and Mass

Concept Description Role in Spring Balance
Mass Amount of matter in an object; constant property. What we want to measure (ideally).
Weight Force of gravity on an object ($W = mg$); varies with 'g'. What the spring balance actually measures.
Acceleration due to gravity (g) Force per unit mass due to gravity; varies with location. Affects weight, causing spring balance reading to vary for the same mass at different locations.
Calibration Process of setting the spring balance scale to show mass units assuming a specific 'g'. Determines the reference 'g' against which subsequent measurements are compared.

Additional Information on Spring Balance Usage

While a spring balance measures weight, it is often used in everyday life to measure mass because it is convenient and gravity variations are small in many regions. However, for accurate mass measurement, especially in scientific contexts or across significant geographical differences (like from sea level to a mountaintop, or between poles and the equator), other instruments like a beam balance (which compares the unknown mass to known standard masses, unaffected by local gravity) are preferred.

The statement highlights the critical factor for accurate mass reading on a spring balance: the consistency of the acceleration due to gravity between the measurement location and the calibration location. If these two values are the same, the ratio \(g_{local} / g_{calibration}\) is 1, and the reading \(R\) correctly equals the mass \(m\).

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Important Questions from Newton's Laws of Motion

  1. Weight and mass of an object are defined with Newton’s laws of motion. Which among the following is true ?

  2. Which one of the following is not a contact force?

  3. A ball is thrown vertically upward from the ground with a speed of 25.2 m/s. The ball will reach the highest point of its journey in

  4. When a force of 1 newton act on a mass of 1 kg which is able to move freely, the object moves in the direction of fore with a/an

  5. How is the kinetic energy of a moving object effected If the net work done on it is positive?

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