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Question

Which ONE of the following options CORRECTLY matches the matrices to their properties?

 

 Matrix Property
P$ \begin{bmatrix} -30 & 17 & 5 \\ 17 & 0 & -12 \\ 5 & -12 & 4 \end{bmatrix} $1Singular
Q$ \begin{bmatrix} 0 & 1 & 9 \\ 7 & 0 & 2 \\ 12 & 3 & 0 \end{bmatrix} $2Triangular
R$ \begin{bmatrix} 2/3 & 1/3 & 2/3 \\ 0 & 2/3 & -1/3 \\ 0 & 4/3 & -2/3 \end{bmatrix} $3Symmetric
S$ \begin{bmatrix} 1 & 2 & 3 \\ 0 & 1 & 4 \\ 0 & 0 & 1 \end{bmatrix} $4Trace free

The correct answer is
P-3; Q-4; R-1; S-2

Matrix P: Symmetric Property Check

Matrix P is given by: $ P = \begin{bmatrix} -30 & 17 & 5 \\ 17 & 0 & -12 \\ 5 & -12 & 4 \end{bmatrix} $ A matrix is symmetric if it is equal to its transpose ($P = P^T$), meaning $P_{ij} = P_{ji}$ for all i, j.

  • $P_{12} = 17$ and $P_{21} = 17$
  • $P_{13} = 5$ and $P_{31} = 5$
  • $P_{23} = -12$ and $P_{32} = -12$

Since $P_{ij} = P_{ji}$ for all elements, Matrix P is symmetric (Property 3).

Matrix Q: Trace Free Property Check

Matrix Q is given by: $ Q = \begin{bmatrix} 0 & 1 & 9 \\ 7 & 0 & 2 \\ 12 & 3 & 0 \end{bmatrix} $ A matrix is trace free if the sum of its diagonal elements (its trace) is zero.

Trace(Q) = $ Q_{11} + Q_{22} + Q_{33} $ Trace(Q) = $ 0 + 0 + 0 = 0 $

Since the trace is 0, Matrix Q is trace free (Property 4).

Matrix R: Singular Property Check

Matrix R is given by: $ R = \begin{bmatrix} 2/3 & 1/3 & 2/3 \\ 0 & 2/3 & -1/3 \\ 0 & 4/3 & -2/3 \end{bmatrix} $ A matrix is singular if its determinant is zero.

Calculate the determinant of R: det(R) = $ \frac{2}{3} \left( \frac{2}{3} \cdot \frac{-2}{3} - \left(-\frac{1}{3}\right) \cdot \frac{4}{3} \right) - \frac{1}{3} (0 \cdot \frac{-2}{3} - \left(-\frac{1}{3}\right) \cdot 0) + \frac{2}{3} (0 \cdot \frac{4}{3} - \frac{2}{3} \cdot 0) $ det(R) = $ \frac{2}{3} \left( \frac{-4}{9} + \frac{4}{9} \right) - \frac{1}{3}(0) + \frac{2}{3}(0) $ det(R) = $ \frac{2}{3} (0) - 0 + 0 = 0 $

Since det(R) = 0, Matrix R is singular (Property 1).

Matrix S: Triangular Property Check

Matrix S is given by: $ S = \begin{bmatrix} 1 & 2 & 3 \\ 0 & 1 & 4 \\ 0 & 0 & 1 \end{bmatrix} $ A matrix is triangular if all the entries above or below the main diagonal are zero. This matrix has zeros below the main diagonal ($S_{21}=0, S_{31}=0, S_{32}=0$).

Therefore, Matrix S is triangular (Property 2).

Summary of Matches

The correct matches are:

Matrix Property
P 3 (Symmetric)
Q 4 (Trace free)
R 1 (Singular)
S 2 (Triangular)

This corresponds to the option P-3; Q-4; R-1; S-2.

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Important Questions from Matrix Algebra

  1. If A = \( \left[\begin{array}{cc}0 & 1 \\ −1 & 0\end{array}\right]\)  and (aI 2  + bA)2  = A, then
  2. If A = \(\left[\begin{array}{cc}2 & −3 \\3 & 5\end{array}\right]\), then which of the following statements are correct?

    A. A is a square matrix

    B. A−1 exists

    C. A is a symmetric matrix

    D. |A| = 19

    E. A is a null matrix

    Choose the correct answer from the options given below.

  3. If A is Square Matrix of order 3, then product of A and its transpose is

  4. What is the transformation matrix M that transforms a square in the xy-plane defined by (1, 1) T, (-1, 1) T, (-1, -1) T and (1, -1) T to a parallelogram whose corresponding vertices are (2, 1) T, (0, 1) T, (-2, -1) T and (0, -1) T?

  5. Let \(A = \left[ {\begin{array}{*{20}{c}} 1&1&0\\ 0&1&0\\ 1&1&0\\ 0&0&1 \end{array}} \right]\) and  \(B = \left[ {\begin{array}{*{20}{c}} 1&0&0&0\\ 0&1&1&0\\ 1&0&1&1\\ \end{array}} \right]\) Find the boolean product A ⊙ B of the two matrices.

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