Which of the following statements is not true?
Every integer is a whole number.
Let's analyze each statement by understanding the definitions of natural numbers, whole numbers, and integer numbers.
We can see a relationship between these sets:
Natural Numbers $\subset$ Whole Numbers $\subset$ Integers
This means that every natural number is a whole number, and every whole number is an integer. Consequently, every natural number is also an integer.
Now let's check each statement given in the question:
Natural numbers start from 1. Whole numbers include 0 and all natural numbers (1, 2, 3,...). Since every natural number is present in the set of whole numbers, this statement is true.
Integers include negative numbers (..., -3, -2, -1), zero (0), and positive numbers (1, 2, 3,...). Whole numbers include only zero (0) and positive numbers (1, 2, 3,...). Negative integers like -1, -2, etc., are integers but are not whole numbers. Therefore, this statement is not true.
Natural numbers start from 1. Integers include all whole numbers (which include natural numbers) and negative numbers. Since every natural number (1, 2, 3,...) is present in the set of integers, this statement is true.
The question asks which statement is not true. Based on our evaluation, the statement "Every integer is a whole number" is the one that is not true.
Suppose a2 + b2 = 4(a + 3b -10), where a and b are two real numbers. Then which of the following is true?
If m and n are two positive real numbers such that 9m2 + n2 = 40 and mn = 4, then the value of 3m + n is:
Consider the following statements :
1. If n is a natural number, then the number \(\frac{n\left(n^2+2\right)}{3}\) is also a natural number.
2. If m is an odd integer, then the number \(\frac{\mathrm{m}^4+4 \mathrm{~m}^2+11}{16}\) is an integer.
Which of the statements given above is/are correct ?
Which composite number can divide the sum of the first 12 natural numbers?
A whole number is added to 100 and the same number is subtracted from 100. the sum of the two resulting numbers so obtained is :