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Question

Which of the following statement is true about the geometric series

 $ 1 + r +r^2 + r^3 + ...............; (r > 0) $?

The correct answer is
It converges, if $ 0 < r < 1 $ and diverges, if $ r\ge 1 $

Understanding Geometric Series Convergence

The question asks us to determine the conditions under which the given geometric series, $ 1 + r + r^2 + r^3 + \dots $, converges or diverges. We are given the constraint that the common ratio $ r $ must be greater than 0 (i.e., $ r > 0 $).

A geometric series is characterized by a first term and a common ratio ($ r $). Each term in the series is obtained by multiplying the previous term by this common ratio. The general form is $ a + ar + ar^2 + ar^3 + \dots $.

Standard Convergence Rule for Geometric Series

The behavior (convergence or divergence) of an infinite geometric series depends critically on the value of its common ratio, $ r $. The standard mathematical rule is:

  • Convergence: The series converges if the absolute value of the common ratio is strictly less than 1. Mathematically, this is expressed as $ |r| < 1 $.
  • Divergence: The series diverges if the absolute value of the common ratio is greater than or equal to 1. Mathematically, this is expressed as $ |r| \ge 1 $.

Applying the Rule with the Given Condition ($ r > 0 $)

For the specific series $ 1 + r + r^2 + r^3 + \dots $, the first term $ a = 1 $ and the common ratio is $ r $. We are given that $ r > 0 $. Let's apply the standard convergence rule under this condition:

Convergence Case: $ 0 < r < 1 $

When the common ratio $ r $ is between 0 and 1 (i.e., $ 0 < r < 1 $), it satisfies the condition $ |r| < 1 $ because $ r $ is positive. Therefore, in this interval, the geometric series converges.

Divergence Case: $ r \ge 1 $

When the common ratio $ r $ is greater than or equal to 1 (i.e., $ r \ge 1 $), it satisfies the condition $ |r| \ge 1 $ because $ r $ is positive. Therefore, in this interval, the geometric series diverges.

Evaluating the Options Provided

Let's examine each option in light of our analysis:

Option 1 Analysis

Statement: "It diverges, if $ 0 < r < 1 $ and converges, if $ r\ge 1 $". This statement incorrectly assigns the conditions. Our analysis shows the opposite is true.

Option 2 Analysis

Statement: "It converges, if $ 0 < r < 1 $ and diverges, if $ r\ge 1 $". This statement accurately reflects the convergence and divergence conditions for the given geometric series with $ r > 0 $. This aligns with our derived results.

Option 3 Analysis

Statement: "It is always convergent". This is false because the series diverges when $ r \ge 1 $.

Option 4 Analysis

Statement: "It is always divergent". This is false because the series converges when $ 0 < r < 1 $.

Option 5 Analysis

This option is empty and does not present a valid statement.

Conclusion

The geometric series $ 1 + r + r^2 + r^3 + \dots $ converges when the common ratio $ r $ is between 0 and 1 ($ 0 < r < 1 $) and diverges when the common ratio $ r $ is 1 or greater ($ r \ge 1 $).

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Important Questions from Progression (Notes)

  1. The sum of 16 terms of the series $\sqrt{2} + \sqrt{8} + \sqrt{18} + \sqrt{32} + .....$ is :
  2. A pilgrim starts walking for a journey of 115 km. On the first day he covers 7 km, the next day 9 km, and likewise keeps adding 2 km everyday till he reaches 15 km per day which he maintains for the rest of the journey. How many days in all will he take to complete the journey?
  3. If a, b and c are in Geometric Progression and $a^\frac{1}{x} = b^\frac{1}{y} = c^\frac{1}{z}$ then, x, y, z are in ________.

  4. $6240$ रुपये की राशि $30$ किस्तों में इस प्रकार चुकाई जाती है कि प्रत्येक किस्त पिछली किस्त से $10$ रुपये अधिक है । पहली किस्त की मूल्य ____________है।

  5. The sum of the cubes of first 'n' natural numbers is 784.
    What is the square of the sum of those 'n' numbers?
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