A. Width of central maxima increases with increase in wavelength keeping slit width constant.
B. Width of central maxima increases with decrease in wavelength keeping slit width constant.
C. Width of central maxima increases with decrease in slit width at constant wavelength.
D. Width of central maxima increases with increase in slit width at constant wavelength.
E. Brightness of central maxima increases for decrease in wavelength at constant slit width.
This question asks about the factors affecting the width and brightness of the central maxima in single-slit diffraction.
The width of the central maxima ($W$) in single-slit diffraction is determined by the positions of the first minima. The angular positions of the minima are given by the equation:
$ \sin \theta_m = \frac{m \lambda}{a} $
where $m = \pm 1, \pm 2, \dots$ is the order number, $\lambda$ is the wavelength of light, and $a$ is the slit width.
For the first minima ($m = \pm 1$), the angular positions are $\pm \frac{\lambda}{a}$. The width of the central maxima on a screen at distance $L$ is approximately:
$ W \approx L \tan \theta_1 \approx \frac{2 \lambda L}{a} $
From this formula, we can analyze the statements:
The peak intensity ($I_{max}$) of the central maxima in single-slit diffraction is approximately proportional to the square of the slit width:
$ I_{max} \propto a^2 $
The intensity distribution also depends on the wavelength, but the peak intensity itself, at the center, primarily depends on the slit width for a given incident light intensity.
Based on the analysis, the true statements are A and C.
The correct option is the one that includes only statements A and C.