The given table presents the percentage distribution of teachers and ratio of male to female teachers working in a university in six different subjects (A‐F). There is a total number of 1600 teachers in the University. Based on the data in the table, answer the questions that follow Subject‐wise Distribution of Teachers Subjects Percentage (%) of Teachers Ratio of Male to Female Teachers A 13% 1 : 7 B 18% 5 : 3 C 12% 1 : 3 D 21% 3 : 4 E 14% 9 : 5 F 22% 7 : 9
Which is the ratio of the number of female teachers in Subject‐E to the number of male teachers in Subject‐D?
5 : 9
The problem asks us to find the ratio of female teachers in Subject E to male teachers in Subject D, based on the provided table showing the percentage distribution of teachers across subjects and the ratio of male to female teachers within each subject.
We are given that the total number of teachers in the university is 1600.
According to the table, 14% of the total teachers work in Subject E.
Total teachers in Subject E = 14% of 1600
\(\text{Total teachers in E} = \frac{14}{100} \times 1600\)
\(\text{Total teachers in E} = 14 \times 16\)
\(\text{Total teachers in E} = 224\)
The ratio of Male to Female teachers in Subject E is given as 9:5.
The total parts in the ratio for Subject E are \(9 + 5 = 14\).
The fraction of female teachers in Subject E is \(\frac{5}{14}\).
Number of female teachers in Subject E = \(\frac{5}{14}\) of Total teachers in Subject E
\(\text{Female teachers in E} = \frac{5}{14} \times 224\)
\(\text{Female teachers in E} = 5 \times \frac{224}{14}\)
\(\text{Female teachers in E} = 5 \times 16\)
\(\text{Female teachers in E} = 80\)
According to the table, 21% of the total teachers work in Subject D.
Total teachers in Subject D = 21% of 1600
\(\text{Total teachers in D} = \frac{21}{100} \times 1600\)
\(\text{Total teachers in D} = 21 \times 16\)
\(\text{Total teachers in D} = 336\)
The ratio of Male to Female teachers in Subject D is given as 3:4.
The total parts in the ratio for Subject D are \(3 + 4 = 7\).
The fraction of male teachers in Subject D is \(\frac{3}{7}\).
Number of male teachers in Subject D = \(\frac{3}{7}\) of Total teachers in Subject D
\(\text{Male teachers in D} = \frac{3}{7} \times 336\)
\(\text{Male teachers in D} = 3 \times \frac{336}{7}\)
\(\text{Male teachers in D} = 3 \times 48\)
\(\text{Male teachers in D} = 144\)
We need to find the ratio of (Female teachers in E) : (Male teachers in D).
Ratio = 80 : 144
To simplify the ratio, we find the greatest common divisor (GCD) of 80 and 144. Both numbers are divisible by 8.
\(\frac{80}{8} = 10\)
\(\frac{144}{8} = 18\)
The ratio becomes 10 : 18. Both numbers are divisible by 2.
\(\frac{10}{2} = 5\)
\(\frac{18}{2} = 9\)
The simplified ratio is 5 : 9.
Thus, the ratio of the number of female teachers in Subject E to the number of male teachers in Subject D is 5 : 9.
| Subject | Total Teachers Calculation | Gender Ratio (M:F) | Specific Gender Count |
|---|---|---|---|
| E | \(14\% \text{ of } 1600 = 224\) | 9 : 5 (Total 14 parts) | Female: \(\frac{5}{14} \times 224 = 80\) |
| D | \(21\% \text{ of } 1600 = 336\) | 3 : 4 (Total 7 parts) | Male: \(\frac{3}{7} \times 336 = 144\) |
Ratio of Female teachers in E to Male teachers in D = 80 : 144 = 5 : 9.
| Concept | Explanation | Application in Problem |
|---|---|---|
| Percentage Calculation | Finding a part of a whole based on a given percentage: \(\frac{\text{Percentage}}{100} \times \text{Whole}\) | Calculating total teachers in Subjects E and D from the university total. |
| Ratio and Proportion | Dividing a quantity based on a given ratio. If a quantity is divided in ratio \(a:b\), the total parts are \(a+b\). The first part is \(\frac{a}{a+b}\) of the quantity, the second is \(\frac{b}{a+b}\). | Calculating the number of female teachers in Subject E (using 9:5 ratio) and male teachers in Subject D (using 3:4 ratio). |
| Ratio Simplification | Dividing both parts of a ratio by their greatest common divisor (GCD) to express it in its simplest form. | Simplifying the ratio 80:144 to its simplest form 5:9. |
When working with data interpretation problems involving tables and percentages, consider these tips:
The table shows District-wise data of a number of primary school teachers posted in schools of a city.
Study the table and answer the question:
District | Male teachers | Female teachers |
East | 1650 | 2375 |
North | 1075 | 2651 |
West | 1280 | 1520 |
South | 1170 | 1085 |
Central | 690 | 859 |
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Source | Amit | Suresh | Nitin | Varun |
Salary | 35000 | 38500 | 29000 | 42000 |
Arrears | 6000 | 6300 | 5000 | 7500 |
Bonus | 1000 | 1100 | 1000 | 1240 |
Overtime | 1800 | 1950 | 1400 | 1500 |
Study the table and answer the question:
Income (Rs.) | No. of persons |
Less than 200 | 12 |
Less than 250 | 26 |
Less than 300 | 34 |
Less than 350 | 40 |
Less than 400 | 50 |
The following table shows the annual profit of a company (in Rs. lakh).
2014-2015 | 2015-2016 | 2016-0217 | 2017-2018 | 2018-2019 |
625 | 690 | 725 | 775 | 815 |
The period which has the maximum percentage increase in profit over the previous year is:
The table given below shows the number of persons participating in a survey from 6 different states.
| States | Persons |
| S1 | 100 |
| S2 | 200 |
| S3 | 400 |
| S4 | 500 |
| S5 | 600 |
| S6 | 800 |
What is the ratio of number of person participating in a survey from state S3 to the number of person participating in a survey from state S4?