When x is added to each of the numbers 11, 18, 27, 42, the numbers so obtained are in proportion. What is the mean proportional between (11x + 3) and (9x - 2)?
30
The problem states that when a number, let's call it \(x\), is added to each of the numbers 11, 18, 27, and 42, the resulting numbers are in proportion.
Numbers in proportion mean that the ratio of the first two numbers is equal to the ratio of the last two numbers. So, if the numbers are \(a, b, c, d\), they are in proportion if \(\frac{a}{b} = \frac{c}{d}\).
After adding \(x\) to each number, the new numbers are:
Since these numbers are in proportion, we can write the equation:
\(\frac{11 + x}{18 + x} = \frac{27 + x}{42 + x}\)
To solve for \(x\), we can cross-multiply:
\((11 + x)(42 + x) = (27 + x)(18 + x)\)
Now, we expand both sides of the equation:
\(11 \times 42 + 11x + 42x + x^2 = 27 \times 18 + 27x + 18x + x^2\)
\(462 + 53x + x^2 = 486 + 45x + x^2\)
We can subtract \(x^2\) from both sides of the equation:
\(462 + 53x = 486 + 45x\)
Now, we collect the \(x\) terms on one side and the constant terms on the other side:
\(53x - 45x = 486 - 462\)
\(8x = 24\)
Finally, we solve for \(x\):
\(x = \frac{24}{8}\)
\(x = 3\)
So, the value of \(x\) is 3.
The second part of the question asks for the mean proportional between \((11x + 3)\) and \((9x - 2)\).
The mean proportional between two numbers \(a\) and \(b\) is given by the square root of their product, i.e., \(\sqrt{a \times b}\).
First, we need to find the values of the two expressions using the value of \(x=3\) we just found:
Expression 1: \(11x + 3\)
Substitute \(x=3\): \(11(3) + 3 = 33 + 3 = 36\)
Expression 2: \(9x - 2\)
Substitute \(x=3\): \(9(3) - 2 = 27 - 2 = 25\)
Now, we need to find the mean proportional between 36 and 25.
Mean Proportional \( = \sqrt{36 \times 25}\)
Mean Proportional \( = \sqrt{900}\)
The square root of 900 is 30 because \(30 \times 30 = 900\).
Mean Proportional \( = 30\)
Thus, the mean proportional between \((11x + 3)\) and \((9x - 2)\) is 30.
| Step | Calculation | Result |
|---|---|---|
| Proportion Equation | \(\frac{11 + x}{18 + x} = \frac{27 + x}{42 + x}\) | Equation formed |
| Solve for \(x\) | \(8x = 24\) | \(x = 3\) |
| Value of \(11x + 3\) | \(11(3) + 3\) | 36 |
| Value of \(9x - 2\) | \(9(3) - 2\) | 25 |
| Mean Proportional | \(\sqrt{36 \times 25} = \sqrt{900}\) | 30 |
| Concept | Definition/Formula | Application in Problem |
|---|---|---|
| Proportion | Four numbers \(a, b, c, d\) are in proportion if \(\frac{a}{b} = \frac{c}{d}\). This is also written as \(a : b :: c : d\). | Used to set up the equation involving \(x\). |
| Cross-multiplication | If \(\frac{a}{b} = \frac{c}{d}\), then \(ad = bc\). Used to solve proportion equations. | Applied to solve for \(x\). |
| Mean Proportional | The mean proportional between two numbers \(a\) and \(b\) is \(\sqrt{a \times b}\). | Used to find the final answer after calculating the expressions. |
Solving algebraic equations involves finding the value(s) of the variable that make the equation true. In this problem, we solved a linear equation after expanding and simplifying the proportion.
Steps often involved:
In our case, after expansion and cancellation of \(x^2\), we had \(462 + 53x = 486 + 45x\). We moved \(45x\) to the left (\(53x - 45x = 8x\)) and 462 to the right (\(486 - 462 = 24\)), resulting in \(8x = 24\), which was easily solved.
The ratio of the third proportion of 5 and 12 with the fourth proportion of 5, 8 and 9 is:
A, B and C start a business. A invests for 3 months, B for 4 months, and C for 6 months. C invests Rs. 2400. If A's share of profit is $\frac{2}{3}$ of B's share, and C's share of profit is $\frac{1}{2}$ of the total profit, how much money did A and B invest?
Divide Rs. 156 in the ratio 1 : 2 : 4 : 5. The rupees in the respective ratios are given by:
A. 13, 26, 53 & 64
B. 13, 26, 51 & 66
C. 13, 26, 52 & 65
D. 13, 25, 53 & 65Divide Rs. 368 in the ratio 1:5:8:9. The rupees in the respective rations are give by.
A. 16, 80, 127 & 145
B. 16, 80, 129 & 143
C. 16, 80, 128 & 144
D. 16, 80, 128 & 143
If A ∶ B = 5 ∶ 4, B ∶ C = 6 ∶ 5, C ∶ D = 7 ∶ 10, then what is the value of A ∶ D?