A, B and C start a business. A invests for 3 months, B for 4 months, and C for 6 months. C invests Rs. 2400. If A's share of profit is $\frac{2}{3}$ of B's share, and C's share of profit is $\frac{1}{2}$ of the total profit, how much money did A and B invest?
A $\rightarrow$ Rs. 1920; B $\rightarrow$ Rs. 2160
This problem involves calculating the initial investments made by business partners A and B, based on their investment durations, C's investment, and specific profit-sharing conditions.
Let's break down the information given:
The profit share in a partnership is generally proportional to the product of the investment amount and the duration for which it was invested. That is, Profit $\propto$ Investment $\times$ Time.
So, the ratio of profits is:
$P_A : P_B : P_C = (I_A \times T_A) : (I_B \times T_B) : (I_C \times T_C)$
Substituting the given time periods:
$P_A : P_B : P_C = (I_A \times 3) : (I_B \times 4) : (I_C \times 6)$
Now, let's use the given profit share relationships to find the ratio $P_A : P_B : P_C$ directly.
We know $P_C = \frac{1}{2} P_{Total}$. Since the total profit is the sum of individual profits ($P_{Total} = P_A + P_B + P_C$), this implies:
$P_C = \frac{1}{2} (P_A + P_B + P_C)$
Multiplying by 2:
$2 P_C = P_A + P_B + P_C$
Rearranging the terms gives:
$P_C = P_A + P_B$
We are also given $P_A = \frac{2}{3} P_B$. Substitute this into the equation $P_C = P_A + P_B$:
$P_C = (\frac{2}{3} P_B) + P_B$
$P_C = (\frac{2}{3} + 1) P_B$
$P_C = \frac{5}{3} P_B$
Now we can establish the ratio between the profits:
$P_A : P_B : P_C = \frac{2}{3} P_B : P_B : \frac{5}{3} P_B$
To simplify this ratio, we can divide each term by $P_B$:
$\frac{2}{3} : 1 : \frac{5}{3}$
To get whole numbers, multiply every part of the ratio by 3:
$(\frac{2}{3} \times 3) : (1 \times 3) : (\frac{5}{3} \times 3)$
$2 : 3 : 5$
So, the profit sharing ratio is $P_A : P_B : P_C = 2 : 3 : 5$.
We have established two ways to represent the profit ratios:
Let's equate these ratios:
$3I_A : 4I_B : 6I_C = 2 : 3 : 5$
We know $I_C = 2400$ and $T_C = 6$. The investment-time product for C is:
$I_C \times T_C = 2400 \times 6 = 14400$
Now, we can relate the parts of the ratio corresponding to C:
$6I_C$ in the first ratio corresponds to $5$ in the second ratio.
So, $14400$ corresponds to $5$ parts of the profit ratio.
Let's find the value of one part:
Value of 1 part $= \frac{14400}{5} = 2880$
Now we can find the values corresponding to A and B in the investment-time product ratio:
For A: $3I_A$ corresponds to $2$ parts.
$3I_A = 2 \times (\text{Value of 1 part}) = 2 \times 2880 = 5760$
For B: $4I_B$ corresponds to $3$ parts.
$4I_B = 3 \times (\text{Value of 1 part}) = 3 \times 2880 = 8640$
Finally, calculate the investments $I_A$ and $I_B$:
Investment of A ($I_A$):
$3I_A = 5760 \implies I_A = \frac{5760}{3} = 1920$
Investment of B ($I_B$):
$4I_B = 8640 \implies I_B = \frac{8640}{4} = 2160$
Therefore, A invested Rs. 1920 and B invested Rs. 2160.
When x is added to each of the numbers 11, 18, 27, 42, the numbers so obtained are in proportion. What is the mean proportional between (11x + 3) and (9x - 2)?
The ratio of the third proportion of 5 and 12 with the fourth proportion of 5, 8 and 9 is:
Divide Rs. 156 in the ratio 1 : 2 : 4 : 5. The rupees in the respective ratios are given by:
A. 13, 26, 53 & 64
B. 13, 26, 51 & 66
C. 13, 26, 52 & 65
D. 13, 25, 53 & 65Divide Rs. 368 in the ratio 1:5:8:9. The rupees in the respective rations are give by.
A. 16, 80, 127 & 145
B. 16, 80, 129 & 143
C. 16, 80, 128 & 144
D. 16, 80, 128 & 143
If A ∶ B = 5 ∶ 4, B ∶ C = 6 ∶ 5, C ∶ D = 7 ∶ 10, then what is the value of A ∶ D?