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Question

When port 1 of two-port circuit is short-circuited, I 1 = 4I 2  & V 2  = 0.25 I 2 . Which of the following is true?

The correct answer is Y 12 = 16

Two-Port Network Fundamentals

Two-port networks are essential models in electrical engineering used to represent and analyze various electronic circuits such as amplifiers, filters, and matching networks. These networks have an input port and an output port, each characterized by a pair of terminals. To describe the behavior of these networks, different parameter sets are used, including Z-parameters (impedance), Y-parameters (admittance), H-parameters (hybrid), and ABCD-parameters (transmission).

Y-Parameters Definition

The admittance parameters, or Y-parameters, relate the currents at the ports to the voltages across the ports. They are particularly useful when a circuit is analyzed under short-circuit conditions, as admittance is the ratio of current to voltage. The standard Y-parameter equations for a linear two-port network are:

  • \( I_1 = Y_{11}V_1 + Y_{12}V_2 \)
  • \( I_2 = Y_{21}V_1 + Y_{22}V_2 \)

Where:

  • \( I_1 \) is the current flowing into port 1.
  • \( V_1 \) is the voltage across port 1.
  • \( I_2 \) is the current flowing into port 2.
  • \( V_2 \) is the voltage across port 2.

The individual Y-parameters are defined under specific short-circuit conditions:

  • \( Y_{11} \): Input Admittance when port 2 is short-circuited (\( V_2 = 0 \)). \( Y_{11} = \frac{I_1}{V_1} \Big|_{V_2=0} \)
  • \( Y_{12} \): Reverse Transfer Admittance when port 1 is short-circuited (\( V_1 = 0 \)). \( Y_{12} = \frac{I_1}{V_2} \Big|_{V_1=0} \)
  • \( Y_{21} \): Forward Transfer Admittance when port 2 is short-circuited (\( V_2 = 0 \)). \( Y_{21} = \frac{I_2}{V_1} \Big|_{V_2=0} \)
  • \( Y_{22} \): Output Admittance when port 1 is short-circuited (\( V_1 = 0 \)). \( Y_{22} = \frac{I_2}{V_2} \Big|_{V_1=0} \)

Short-Circuit Condition at Port 1

The question specifies that port 1 of the two-port circuit is short-circuited. This means the voltage across port 1, \( V_1 \), is zero (\( V_1 = 0 \)).

Let's substitute \( V_1 = 0 \) into the general Y-parameter equations:

  1. From the first equation: \( I_1 = Y_{11}(0) + Y_{12}V_2 \) This simplifies to: \( I_1 = Y_{12}V_2 \) From this, we can define \( Y_{12} \) as: \( Y_{12} = \frac{I_1}{V_2} \) (when \( V_1 = 0 \))
  2. From the second equation: \( I_2 = Y_{21}(0) + Y_{22}V_2 \) This simplifies to: \( I_2 = Y_{22}V_2 \) From this, we can define \( Y_{22} \) as: \( Y_{22} = \frac{I_2}{V_2} \) (when \( V_1 = 0 \))

Calculating Y-Parameters from Given Relations

We are provided with two relationships that hold true when port 1 is short-circuited:

  • \( I_1 = 4I_2 \)
  • \( V_2 = 0.25 I_2 \)

Calculating Y12

We use the expression for \( Y_{12} \) derived under the \( V_1 = 0 \) condition: \( Y_{12} = \frac{I_1}{V_2} \)

Now, we substitute the given relationships into this expression.

First, substitute \( I_1 = 4I_2 \) into the numerator: \( Y_{12} = \frac{4I_2}{V_2} \)

Next, substitute \( V_2 = 0.25 I_2 \) into the denominator: \( Y_{12} = \frac{4I_2}{0.25I_2} \)

Assuming \( I_2 \) is not zero (which it must be for a meaningful relationship), we can cancel \( I_2 \) from the numerator and denominator: \( Y_{12} = \frac{4}{0.25} \) To simplify the division by 0.25, which is equivalent to \( \frac{1}{4} \): \( Y_{12} = \frac{4}{\frac{1}{4}} \) \( Y_{12} = 4 \times 4 \) \( Y_{12} = 16 \)

So, the value of \( Y_{12} \) is 16.

Calculating Y22 (Optional Verification)

Let's also calculate \( Y_{22} \) to check other options, using its definition under \( V_1 = 0 \): \( Y_{22} = \frac{I_2}{V_2} \)

Substitute the given relation \( V_2 = 0.25 I_2 \) into the denominator: \( Y_{22} = \frac{I_2}{0.25I_2} \)

Cancel \( I_2 \) from the numerator and denominator: \( Y_{22} = \frac{1}{0.25} \) \( Y_{22} = 4 \)

Thus, \( Y_{22} = 4 \).

Evaluating the Given Options

Based on our analysis and calculations when port 1 is short-circuited:

  • Option 1: Y11 = 4 The parameter \( Y_{11} \) is defined as \( \frac{I_1}{V_1} \) when port 2 is short-circuited (\( V_2 = 0 \)). The problem specifies port 1 is short-circuited (\( V_1 = 0 \)), which prevents direct calculation of \( Y_{11} \) from the provided conditions. Therefore, this statement cannot be confirmed as true or false with the given information.
  • Option 2: Y12 = 16 Our calculation directly yields \( Y_{12} = 16 \). This statement is true based on the given conditions.
  • Option 3: Y21 = 16 The parameter \( Y_{21} \) is defined as \( \frac{I_2}{V_1} \) when port 2 is short-circuited (\( V_2 = 0 \)). Similar to \( Y_{11} \), the given condition of \( V_1 = 0 \) does not allow for direct calculation of \( Y_{21} \). This statement cannot be confirmed.
  • Option 4: Y22 = 0.25 Our calculation shows that \( Y_{22} = 4 \), which contradicts this option. Therefore, this statement is false.

Based on the detailed analysis and calculations, the only statement that is true given the conditions is \( Y_{12} = 16 \).

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Important Questions from Two Port Networks

  1. A Two - port network is reciprocal if and only if:

  2. Read the following statements regarding two port networks.

    (A) The condition of reciprocity and symmetry for a two-port network with 'g' parameter representation can be deduced from the interrelationship of 'h' and g parameters.

    (B) The condition of reciprocity for the h parameter representation leads to the condition of reciprocity for 'g' parameters representation as g 12 = −g 21 .

    (C) The condition of symmetry in h-parameters representation never leads to the condition of symmetry in 'g' parameters representation.

    (D) The symmetry condition in 'h' and 'g parameter representation can be deduced by putting h 11 = g 11 .

    Choose the correct answer from the options given below:

  3. A passive 2-port network is in a steady-state. Compared to its input, the steady state output can never offer ________.

  4. The condition for symmetric property of ABCD parameter of two port network is:

  5. A two-port network has scattering parameters given \(\left[ s \right] = \left[ {\begin{array}{*{20}{c}} {{s_{11}}}&{{s_{12}}}\\ {{s_{211}}}&{{s_{22}}} \end{array}} \right]\). If the port 2 of the two-port is short-circuited, the s11 parameter for the resultant one-port network is

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