Let the original number be represented by '$x$'.
According to the question, when one-third of the number is increased by 37, the result is 51. This can be written as the equation:
$ \frac{1}{3}x + 37 = 51 $
To find the value of '$x$', we first isolate the term with '$x$':
$ \frac{1}{3}x = 51 - 37 $
$ \frac{1}{3}x = 14 $
Now, multiply both sides by 3 to find the value of '$x$':
$ x = 14 \times 3 $
$ x = 42 $
So, the original number is 42.
The question asks for the sum of the digits of the original number (42).
Sum of digits = $4 + 2 = 6$.
Verify the result: One-third of 42 is $ \frac{42}{3} = 14 $. Increasing this by 37 gives $ 14 + 37 = 51 $. This matches the condition given in the problem.
What is the Highest Common Factor of 2 3× 3 5and 3 3× 5 2?
Four prime numbers are arranged in ascending order. The product of the first three numbers is 255 and that of the last three is 1955. The largest prime number is:
Find the number of all prime numbers less than 55.
Value of the square root of \(\frac{36.1}{102.4}\) is:
For any natural number n, 6n - 5n always ends with