Let the original number be represented by '$x$'.
According to the question, when one-third of the number is increased by 37, the result is 51. This can be written as the equation:
$ \frac{1}{3}x + 37 = 51 $
To find the value of '$x$', we first isolate the term with '$x$':
$ \frac{1}{3}x = 51 - 37 $
$ \frac{1}{3}x = 14 $
Now, multiply both sides by 3 to find the value of '$x$':
$ x = 14 \times 3 $
$ x = 42 $
So, the original number is 42.
The question asks for the sum of the digits of the original number (42).
Sum of digits = $4 + 2 = 6$.
Verify the result: One-third of 42 is $ \frac{42}{3} = 14 $. Increasing this by 37 gives $ 14 + 37 = 51 $. This matches the condition given in the problem.
Consider the following statements :
1. (25)! + 1 is divisible by 26
2. (6)! + 1 is divisible by 7
Which of the above statements is/are correct ?
If the sum S is divided by 8, what is the remainder ?
If the sum S is divided by 60, what is the remainder ?
Find the sum of squares of the greatest value and the smallest value of K in the number so that the number 45082K is divisible by 3.
How many composite numbers are there from 53 to 97 ?