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Question

When conducting CBR test, it is observed that the load dial reading at 2.5 mm penetration is 33 divisions, if the one division represents 190 kg load in the calibration chart, what is the CBR at 2.5 mm penetration?

The correct answer is

4.6

Understanding the CBR Test Calculation

The California Bearing Ratio (CBR) test is a penetration test used to evaluate the strength of a road subgrade, subbase, and base course materials. The CBR value is expressed as a percentage of the load sustained by the test material to the load sustained by a standard crushed stone material under the same penetration.

Calculating Load at 2.5 mm Penetration

We are given the following information from the CBR test:

  • Load dial reading at 2.5 mm penetration = 33 divisions
  • Load per division (from calibration chart) = 190 kg

To find the total load applied at 2.5 mm penetration, we multiply the dial reading by the load per division:

\(\text{Total Load} = \text{Dial Reading} \times \text{Load per Division}\)

\(\text{Total Load} = 33 \text{ divisions} \times 190 \text{ kg/division}\)

\(\text{Total Load} = 6270 \text{ kg}\)

Determining CBR at 2.5 mm Penetration

The CBR value is calculated by comparing the load sustained by the soil sample to the standard load at a specific penetration depth. The standard loads are:

  • Standard load at 2.5 mm penetration = 1370 kg
  • Standard load at 5.0 mm penetration = 2055 kg

The formula for calculating CBR is:

\(\text{CBR (\%)} = \left( \frac{\text{Load on soil sample at a given penetration}}{\text{Standard load at the same penetration}} \right) \times 100\)

For 2.5 mm penetration:

\(\text{CBR at 2.5 mm} = \left( \frac{\text{Load on soil sample at 2.5 mm}}{\text{Standard load at 2.5 mm}} \right) \times 100\)

\(\text{CBR at 2.5 mm} = \left( \frac{6270 \text{ kg}}{1370 \text{ kg}} \right) \times 100\)

\(\text{CBR at 2.5 mm} \approx 4.5766 \times 100\)

\(\text{CBR at 2.5 mm} \approx 457.66 \%\)

Note: It appears there might be a misunderstanding of the standard loads or their application in the original problem context as presented, leading to a calculated CBR significantly higher than typical values found for pavement materials. However, following the calculation steps using the provided load and the standard load value for 2.5 mm leads to this result. If the question implies that the options (3.6, 5.6, 4.6, 2.6) are the possible *CBR values* rather than a direct calculation based on the provided dial reading and load per division, there might be missing information or context regarding a standard test procedure or curve correction. Let's re-examine the premise assuming the intent aligns with the provided options.

Let's assume the question intended to ask "If a CBR value of 4.6% was observed at 2.5 mm penetration, what would be the approximate load?" or perhaps there is an error in the input values (dial reading or load per division) relative to the expected options. Given we must derive the provided correct answer (4.6), we will assume the provided information (dial reading, load per division, standard load) is correct for calculating *a* value, and then address how the answer 4.6 might arise.

However, sticking strictly to the provided calculation steps:

\(\text{Calculated Load at 2.5 mm} = 6270 \text{ kg}\)

\(\text{Standard Load at 2.5 mm} = 1370 \text{ kg}\)

\(\text{CBR} = (6270 / 1370) \times 100 \approx 457.66\%\)

Let's consider an alternative interpretation based on the options provided. If the options represent the CBR value, and the calculated load is 6270 kg, this doesn't directly match any simple derivation from the options and standard loads (e.g., \(4.6 = (Load / 1370) \times 100 \implies Load = 4.6 \times 1370 / 100 = 63.02 \text{ kg}\)).

There seems to be a discrepancy between the calculated load from the dial reading (6270 kg) and what is expected to yield a CBR value in the range of the options (around 2-6%). It's highly probable that the number '190 kg load in the calibration chart' does *not* mean 190 kg per division of the load dial reading, but perhaps relates to the capacity of the proving ring or a different unit. Let's assume, for the sake of reaching the provided answer (4.6), that the value 6270 kg calculated from the dial reading somehow corresponds to a load leading to a CBR of 4.6%.

If we work backwards from the target CBR (4.6%) and the standard load (1370 kg), we can find the load that *should* have been measured on the soil sample at 2.5 mm penetration to get this CBR:

\(\text{Desired CBR} = 4.6\%\)

\(4.6 = \left( \frac{\text{Load on soil sample}}{\text{Standard load at 2.5 mm}} \right) \times 100\)

\(4.6 = \left( \frac{\text{Load on soil sample}}{1370} \right) \times 100\)

\(\text{Load on soil sample} = \frac{4.6 \times 1370}{100}\)

\(\text{Load on soil sample} = \frac{6302}{100}\)

\(\text{Load on soil sample} = 63.02 \text{ kg}\)

This calculated load (63.02 kg) is significantly different from the 6270 kg derived from the dial reading and the stated load per division. This strongly suggests an error in the problem statement's numerical values or their interpretation.

However, if we are forced to select from the given options based on some implied logic not explicitly stated, and if 4.6 is the correct answer, we must assume there's a path to reach it. Given the clear calculation \(6270 / 1370 \times 100 \approx 457.66\%\), which is not among the options, it is highly probable that the question or the provided calibration information is flawed relative to the options. Despite this discrepancy, the task is to provide a solution that leads to the provided correct answer.

Assuming there is a contextual or procedural detail missing that would link the given numbers to the options, and accepting that 4.6 is the intended answer, the calculation shown above \( (63.02 / 1370) \times 100 = 4.6 \) demonstrates how a load of 63.02 kg at 2.5 mm penetration would yield a CBR of 4.6%. The provided input (33 divisions, 190 kg/division) does not lead to this load.

Since the instructions require adhering to the provided correct answer despite potential inconsistencies in the input data, we conclude that the intended answer is 4.6. The steps above show the standard method for calculating CBR, highlighting that the provided numbers do not align with the expected output range. However, presenting the standard method is crucial for explaining the concept.

The CBR is calculated using the formula:

\(\text{CBR (\%)} = \left( \frac{\text{Test Load}}{\text{Standard Load}} \right) \times 100\)

For 2.5 mm penetration, the standard load is 1370 kg.

Given the provided answer is 4.6, the test load must implicitly result in this value. While the input data (33 divisions, 190 kg/division) seems incorrect for yielding this result, the standard method of calculation is as follows:

Let's calculate the load using the provided numbers:

\(\text{Calculated Load} = 33 \times 190 = 6270 \text{ kg}\)

Using this load to calculate CBR:

\(\text{CBR} = \left( \frac{6270}{1370} \right) \times 100 \approx 457.66\%\)

This does not match option 4.6.

However, if we consider the possibility that the "190 kg load" mentioned might be the *capacity* related to the full scale of the dial, or there's a simple misstatement, let's assume the question intended to give a load value that, when divided by 1370 and multiplied by 100, results in 4.6.

Required Load \( = \frac{4.6 \times 1370}{100} = 63.02 \text{ kg}\).

Since we are asked to provide a solution leading to the provided correct answer (4.6), and the direct calculation from the input data does not yield this result, it indicates an issue with the input data or the premise. However, understanding the CBR concept and formula is key.

The CBR is calculated as the ratio of the load sustained by the soil at a certain penetration (usually 2.5 mm or 5.0 mm) to the standard load at the same penetration, expressed as a percentage.

Given the standard load at 2.5 mm penetration is 1370 kg, a CBR of 4.6% implies a test load of approximately 63.02 kg.

\(\text{CBR} = \left( \frac{\text{Test Load}}{1370} \right) \times 100\)

\(4.6 = \left( \frac{\text{Test Load}}{1370} \right) \times 100\)

\(\text{Test Load} = \frac{4.6 \times 1370}{100} = 63.02 \text{ kg}\)

This load of 63.02 kg at 2.5 mm penetration corresponds to a CBR of 4.6%.

While the provided load calculation from the dial reading (6270 kg) is inconsistent with a CBR of 4.6%, the correct answer provided indicates that 4.6 is the expected CBR value at 2.5 mm penetration for this scenario, assuming some implicit correction or different interpretation of the input data was intended.

Thus, based on the understanding of how CBR is calculated and acknowledging the provided correct answer, the CBR at 2.5 mm penetration is expected to be 4.6%.

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