When a p-n junction is reverse biased,
Depletion layer increases
This question explores the behavior of a p-n junction when it is subjected to reverse bias. Understanding how reverse biasing affects the depletion layer and the overall resistance is crucial in semiconductor physics.
A p-n junction is formed when a p-type semiconductor (having an excess of holes) is joined with an n-type semiconductor (having an excess of electrons). At the junction, some electrons diffuse into the p-side and holes diffuse into the n-side, creating a region depleted of mobile charge carriers, known as the depletion layer or depletion region. This layer has an associated potential barrier.
Reverse biasing occurs when the positive terminal of an external voltage source is connected to the n-type material and the negative terminal is connected to the p-type material. This is opposite to the condition for forward biasing.
When a p-n junction is reverse biased:
Therefore, when a p-n junction is reverse biased, the depletion layer increases in width.
The increased width of the depletion layer under reverse bias means there are fewer free charge carriers available to conduct current across the junction. This significantly increases the opposition to current flow, meaning the junction offers a high resistance.
Let's examine the given options in the context of a reverse biased p-n junction:
The primary and most significant effect of reverse biasing a p-n junction is the expansion of the depletion layer.
The forward biased diode current is:
Which of the following is a characteristic of a reverse-biased p-n junction?
For every 10°C increase in temperature, the reverse saturation current of a p-n junction will be increased by
For an ideal diode, the ideality factor is
The p-n junction diode has