What will come in place of question mark (?) in the following equation? 20% of 500 ÷ ? + [40% of 400] = 164
25
To find the value that should replace the question mark (?) in the given equation, we need to solve the equation step-by-step.
Calculating Percentage Values
First, let's calculate the percentage values present in the equation:
- Calculate 20% of 500: $$20\% \text{ of } 500 = \frac{20}{100} \times 500$$ $$= 0.20 \times 500$$ $$= 100$$
- Calculate 40% of 400: $$40\% \text{ of } 400 = \frac{40}{100} \times 400$$ $$= 0.40 \times 400$$ $$= 160$$
Simplifying the Equation
Now, substitute these calculated values back into the original equation:
The original equation is: $20\% \text{ of } 500 \div ? + [40\% \text{ of } 400] = 164$
Substituting the values, we get:
$$100 \div ? + [160] = 164$$This simplifies to:
$$100 \div ? + 160 = 164$$Solving for the Unknown Variable
Next, we need to isolate the term containing the question mark (?).
Subtract 160 from both sides of the equation:
$$100 \div ? = 164 - 160$$ $$100 \div ? = 4$$Finally, to solve for ?, we can rearrange the equation. Multiply both sides by ?:
$$100 = 4 \times ?$$Now, divide both sides by 4:
$$? = \frac{100}{4}$$ $$? = 25$$Therefore, the number that comes in place of the question mark is 25.
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Important Questions from Simplification
Simplify
6 × {28 ÷ 84 × {36 × 49 ÷ (6 × 7)}}.
Simplify.
- A bag contains ₹5, 2 and 1 coins in the ratio of 3 : 4 : 5. The total value of all the coins is ₹2,100. How many coins of ₹5 are there in the bag?
- \(\frac{6}{2}\times\frac{10}{2}\div\frac{6}{2}\times6^2+5\times4=?\)
- Find the value of 2.\(\overline {36} \) + 3.\(\overline {21} \) - 1.\(\overline {05} \)
