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Question

What value should come in place of questions (?) in the following equations?

56 × 15 ÷ 3 – 83 = ? – 139

This question was previously asked in
RBI Assistant Prelims Memory Based Paper (27 March 2022) (Shift 2)
The correct answer is

336

Solving the Arithmetic Equation: 56 × 15 ÷ 3 – 83 = ? – 139

This question asks us to find the numerical value that should replace the question mark ('?') in the given arithmetic equation. To solve this, we need to follow the standard order of operations, commonly remembered by the acronym BODMAS or PEMDAS.

Understanding the Order of Operations (BODMAS/PEMDAS)

The BODMAS rule stands for:

  • Brackets
  • Order (powers and square roots, etc.)
  • Division
  • Multiplication
  • Addition
  • Subtraction

Division and Multiplication have the same priority and are performed from left to right. Similarly, Addition and Subtraction have the same priority and are performed from left to right.

Step-by-Step Calculation

Let's break down the equation: 56 × 15 ÷ 3 – 83 = ? – 139

Step 1: Perform Multiplication

First, we calculate the multiplication part: 56 × 15.

$$ 56 \times 15 = 840 $$

The equation now becomes: 840 ÷ 3 – 83 = ? – 139

Step 2: Perform Division

Next, we perform the division: 840 ÷ 3.

$$ 840 \div 3 = 280 $$

The equation simplifies to: 280 – 83 = ? – 139

Step 3: Perform Subtraction on the Left Side

Now, we subtract 83 from 280.

$$ 280 - 83 = 197 $$

The equation is now: 197 = ? – 139

Step 4: Isolate the Question Mark

To find the value of '?', we need to isolate it on one side of the equation. We can do this by adding 139 to both sides of the equation.

$$ ? = 197 + 139 $$

Step 5: Final Calculation

Finally, we add 197 and 139.

$$ 197 + 139 = 336 $$

So, the value that should come in place of the question mark is 336.

Conclusion

By carefully applying the order of operations (BODMAS), we found that the missing value in the equation 56 × 15 ÷ 3 – 83 = ? – 139 is 336.

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Important Questions from Simplification

  1. Simplify

    6 × {28 ÷ 84 × {36 × 49 ÷ (6 × 7)}}.

  2. Simplify.

  3. A bag contains ₹5, 2 and 1 coins in the ratio of 3 : 4 : 5. The total value of all the coins is ₹2,100. How many coins of ₹5 are there in the bag?
  4. \(\frac{6}{2}\times\frac{10}{2}\div\frac{6}{2}\times6^2+5\times4=?\)
  5. Find the value of 2.\(\overline {36} \) + 3.\(\overline {21} \) - 1.\(\overline {05} \)
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