What will be the z-transform of a Unit step function ?
u(t) = z / (z - 1)
The z-transform is a mathematical tool used to convert discrete-time signals from the time domain to the complex frequency domain. It is particularly useful in analyzing and designing digital filters and discrete-time control systems. We will now derive the z-transform of the unit step function.
The unit step function, denoted as \(u[n]\) or \(u(t)\) in discrete time, is a fundamental discrete-time signal. It is defined as follows:
$$ u[n] = \begin{cases} 1 & \text{for } n \ge 0 \\ 0 & \text{for } n < 0 \end{cases} $$
This means that the function has a value of 1 for all non-negative integer values of \(n\) and 0 for all negative integer values of \(n\). This is a crucial signal for understanding system responses and initial conditions in discrete systems.
The unilateral (one-sided) z-transform of a discrete-time signal \(x[n]\) is defined by the following summation formula:
$$ X(z) = \sum_{n=0}^{\infty} x[n]z^{-n} $$
Here, \(z\) is a complex variable. The z-transform converts a sequence of numbers into a function of \(z\), which can simplify the analysis of linear time-invariant (LTI) discrete systems.
To find the z-transform of the unit step function \(u[n]\), we substitute its definition into the z-transform formula:
We start with the general z-transform formula:
$$ U(z) = \sum_{n=0}^{\infty} u[n]z^{-n} $$
Since \(u[n] = 1\) for \(n \ge 0\), we can substitute this value into the summation:
$$ U(z) = \sum_{n=0}^{\infty} (1)z^{-n} $$
This summation can be rewritten as:
$$ U(z) = \sum_{n=0}^{\infty} (z^{-1})^n $$
This is a standard infinite geometric series of the form \(\sum_{n=0}^{\infty} r^n\), where \(r = z^{-1}\). The sum of an infinite geometric series is given by the formula:
$$ \sum_{n=0}^{\infty} r^n = \frac{1}{1 - r} \quad \text{for } |r| < 1 $$
Applying this formula to our expression, with \(r = z^{-1}\):
$$ U(z) = \frac{1}{1 - z^{-1}} $$
To express this in a more common form without negative powers of \(z\), we multiply the numerator and the denominator by \(z\):
$$ U(z) = \frac{1 \cdot z}{(1 - z^{-1}) \cdot z} $$
$$ U(z) = \frac{z}{z - z^{-1} \cdot z} $$
$$ U(z) = \frac{z}{z - 1} $$
This result is valid for \(|z^{-1}| < 1\), which implies \(1/|z| < 1\), or \(|z| > 1\). This region of convergence (ROC) is the exterior of a circle with radius 1 centered at the origin in the z-plane.
Let's compare our derived z-transform of the unit step function with the given options:
Our derived z-transform, \(U(z) = \frac{z}{z - 1}\), directly matches Option 4. This demonstrates the standard result for the z-transform of a unit step function, which is frequently used in discrete-time signal processing and control systems.
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