To find the transient time of a series RC circuit, we calculate the time constant ($\tau$). The time constant represents the time required for the capacitor's voltage to reach approximately 63.2% of its final value during charging or discharge.
The formula for the time constant ($\tau$) in an RC circuit is:
$ \tau = R \times C $
Where:
We are given:
Now, substitute these values into the formula:
$ \tau = (8 \times 10^3 \, \Omega) \times (8 \times 10^{-3} \, \text{F}) $
$ \tau = 64 \times 10^{(3 + (-3))} \, \Omega \cdot \text{F} $
$ \tau = 64 \times 10^0 \, \text{s} $
$ \tau = 64 \times 1 \, \text{s} $
$ \tau = 64 \, \text{s} $
The transient time (time constant) of the series RC circuit is 64 seconds.
The time constant of an inductive circuit is defined as the time required for the circuit current to rise to _____ % (approximately) of its final steady state value.
Which of the following groups have similar units?
Symbols have their own common meanings.
Which of the following is/are not discharging equation/equations for an R-C circuit?
1. Capacitor voltage: \[ v_C = V_0 e^{-\tfrac{t}{RC}} \] 2. Resistor voltage: \[ v_R = E e^{-\tfrac{t}{RC}} \] 3. Discharging current: \[ i = \frac{V_0}{R} e^{-\tfrac{t}{RC}} \]
Select the correct answer using the code given below.
| List-I (Time constant) | List-II (Capacitor discharging voltage) |
| P. $1\tau$ | 1. 0.67% of E |
| Q. $2\tau$ | 2. 36.8% of E |
| R. $3\tau$ | 3. 13.5% of E |
| S. $4\tau$ | 4. 5% of E |
| T. $5\tau$ | 5. 1.87% of E |
What is the voltage across a capacitor after being charged from a 10 V DC source for a period of one time constant?